python - 将方法添加到 ModelViewset Endpoint，而无需调用 URL 中的方法名称

Question

我有两个独立的端点，分别“接受”和“拒绝”系统上的每个申请人。

端点#1:

...api/v1/applicants/{ID}/accept

端点#2:

...api/v1/applicants/{ID}/decline

现在，我正在重构并尝试将 Endpoints 合并为一个，这样可以使用以下 URL accept 和 decline 申请人，同时保持:

...api/v1/applicants/{ID}/

这样做的目的是使端点符合 REST 方法。

我尝试了什么:

我尝试创建一个隐藏方法 [以下划线开头 - 例如:_someFunction() 使用 PUT 请求方法]。这没有用。

我知道我也可以通过 serializers.py 文件来完成，但我不知道如何操作，因为我没有在网上看到示例。

这是 accept 类。 下降类似，只是有一些小的变化:

@action(detail=True, methods=['put'])
def accept(self, request, pk):
    data = request.data

    if request.user.user_type == "2":

        if Applicant.objects.filter(id=pk).exists():
            applicant = Applicant.objects.get(id=pk)
            if applicant.status == '1':
                applicant.status = '2'
                applicant.save()

                # Hash the ID of the particular applicant so it can be used for verification
                # make this a function during refactoring

                hashids = Hashids(salt=HASH_SALT, min_length=16)
                hashid = hashids.encode(applicant.id)

                # send email with the link to the applicant
                # make this a function too

                SENDER="xxx@example.com"
                SUBJECT="Congratulations, you've been accepted!"
                MESSAGE = """

                    Hello {}, \n                    
                    Your application as a Journalist on example.com was accepted.\n 
                    Copy your OTP: {} and Click here "https://example.com/verify-otp/ to enter it.\n
                    Cheers!
                    """.format(applicant.first_name, hashid)

                send_mail(SUBJECT, MESSAGE, SENDER, [applicant.email], fail_silently=False)

                # generate a response object
                queryset = applicant
                serializer = ApplicantSerializer(queryset)
                return Response(jsend.success({'applicants':serializer.data}))

            else:
                return Response((jsend.error("Cannot perform such action for this applicant")), status=status.HTTP_400_BAD_REQUEST)

        else:
            return Response((jsend.error('Cannot find an applicant with ID of {}'.format(pk))), status=status.HTTP_404_NOT_FOUND)
    else:
        return Response((jsend.error("You are not authorized to perform this action")), status=status.HTTP_403_FORBIDDEN)

Answer 1

例如，您可以使用 perform_update 覆盖 ModelViewSet 的 perform_update() 或 update():

 def perform_update(self, serializer):
    applicant = self.get_object()
    if applicant.status == '1':
            serializer.save(status='2')
    #rest of your logic
    serializer.save()

希望对您有所帮助。请注意，您可以像这样在 perform_update 中获取请求:

self.request