ios - 如何在快速单击按钮时更改开关状态

Question

我只是在制作一个基本的应用程序，我可以打开和关闭开关来告诉我一天中某个类(class)是否有作业。我遇到的问题是将所有开关更改为关闭的重置按钮。如何使用按钮快速更改开关状态？这是我到目前为止所拥有的:

//
//  ViewController.swift
//  HomeworkManager
//
//  Created by Nate Parker on 9/2/14.
//  Copyright (c) 2014 Nathan Parker. All rights reserved.
//

import UIKit

class ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


@IBAction func resetClicked(sender: AnyObject) {
}

@IBOutlet var spanish: UISwitch
@IBOutlet var algebra: UISwitch
@IBOutlet var amerCult: UISwitch
@IBOutlet var bio: UISwitch
@IBOutlet var col: UISwitch


}

Answer 1

这应该只是使用 setOn() 的问题开关方法:

@IBAction func resetClicked(sender: AnyObject) {
    spanish.setOn(false, animated: true);
    algebra.setOn(false, animated: true);
    amerCult.setOn(false, animated: true);
    bio.setOn(false, animated: true);
    col.setOn(false, animated: true);
}