我遇到了和上周一样的麻烦。
我的 html 代码如下所示:
<article class="tickets">
<div class="grid_12 left">
<div class="header">
<i class="icon-pushpin"></i>
Neue Tickets
<div class="count right"><span>6</span></div>
</div>
<div class="messages">
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
</div>
<div class="header">
<i class="icon-pushpin"></i>
Neue Tickets
<div class="count right"><span>6</span></div>
</div>
<div class="messages">
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
<div class="msg">
<div class="dreieck prio_a"></div>
<div class="ava right"><img src="http://lorempixel.com/40/40/" alt="Test"></div>
<div class="autor">Lars</div>
<small class="subject">Test</small>
</div>
</div>
</div>
</article>
和 jQuery 部分:
$('.header').click(function(e) {
$(this).siblings('.messages').slideDown(500);
$(this).next().slideUp('normal');
e.preventDefault();
});
第一个菜单上下滑动,第二个菜单向下滑动。 我会向下滑动第一个菜单,然后在单击“标题”后向上滑动。当第一个菜单打开并且您单击第二个菜单时,第一个菜单应该向上滑动,第二个向下滑动。 我的代码有什么问题?
最佳答案
我想这就是你想要的:
$(this).siblings('.messages').not($(this).next('.messages')).slideUp(500);
$(this).next('.messages').slideToggle('normal');
首先,我向上滑动所有 .message
($(this).next('.messages')
除外),然后切换 $(this).next('.messages')
。我使用了切换开关,以便您可以关闭和打开它。
我已经更新了你的jsFiddle
来源
关于jQuery slideDown 菜单不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16439612/