ios - 具有协议(protocol)问题的 Swift 通用 UIView 子类

Question

我扩展了 UIView 以符合 UIGestureRecognizerDelegate 协议(protocol)

下面的代码可以编译

let label = UILabel()
let recognizer = UITapGestureRecognizer(target: label.self, action: Selector("tapGestureHandler:"))
recognizer.delegate = label.self
label.addGestureRecognizer(recognizer)

现在我正在尝试创建一个通用子类来创建不同的 UIView 子类

class MyView<T:UIView> {
    init() {
        (T.self as T.Type).init(frame: CGRectZero)
    }

    func addGestureToView() {
        let recognizer = UITapGestureRecognizer(target: T.self, action: Selector("tapGestureHandler:"))
        // The below two lines produces syntax error    
        recognizer.delegate = T.self // does not conform to protocol 'UIGestureRecognizerDelegate'
        T.addGestureRecognizer(recognizer) // UITapGestureRecognizer cannot convertible to UIView
    }
}

对我来说奇怪的是，T.addGestureRecognizer 需要 UIView 而不是 UIGestureRecognizer

更新:

我希望 MyView 的返回类型是 UIView 的子类，

let view = MyView<UIView>()

//我想这样用

view.tintColor = UIColor.redColor() // I can't

//但是，我必须用这种方式

view.subview.tintColor = UIColor.redColor()

Answer 1

T 是您的 subview 的类型。您必须创建它的实例以调用 addGestureRecognizer 并将其设置为手势识别器的委托(delegate)。

class MyView<T:UIView where T: UIGestureRecognizerDelegate> {
    var subview: T

    init() {
        subview = T(frame: CGRectZero)
    }

    func addGestureToView() {
        let recognizer = UITapGestureRecognizer(target: subview, action: Selector("tapGestureHandler:"))

        recognizer.delegate = subview
        subview.addGestureRecognizer(recognizer)
    }
}

请注意，您假设传递给创建 MyView 实例的类有一个名为 tapGestureHandler: 的方法。您可能应该将此方法添加到协议(protocol)中，并使 T 也符合它。