我是 Swift 的初学者,我正在将应用程序迁移到 Swift 3.0
我一直有这个错误,我不知道如何解决。
“无法使用类型为‘(String)’的参数列表调用‘value’”
它几乎显示在这段代码的每一行。 你知道它可能来自哪里吗? 非常感谢
if ((message as AnyObject).value("content") != nil){
stringContent = (message as AnyObject).value("content") as? String
}
if ((message as AnyObject).value("sender_uuid") != nil){
stringSenderUuid = (message as AnyObject).value("sender_uuid") as? String
}
if ((message as AnyObject).value("recipient_uuid") != nil){
stringRecipientUuid = (message as AnyObject).value("recipient_uuid") as! String
}
if ((message as AnyObject).value("date") != nil){
if let result_number = (message as AnyObject).value("date") as? NSNumber
{
stringDate = "\(result_number)"
}
else {
stringDate = (message as AnyObject).value("date") as! String
}
}
这里要求的是关于消息的更多信息
class Messages: Object {
dynamic var channel_name = ""
dynamic var content = ""
dynamic var sender_uuid = ""
dynamic var recipient_uuid = ""
dynamic var date = ""
dynamic var message_uuid = ""
override class func primaryKey() -> String? {
return "message_uuid"
} }
let message = Messages()
message.channel_name=channel_name
message.content=stringContent
message.sender_uuid = stringSenderUuid
message.recipient_uuid = stringRecipientUuid
message.date = stringDate
message.message_uuid = stringUuid
这里有更多信息
// initialize with nothing
var stringContent = " "
var stringSenderUuid = " "
var stringRecipientUuid = " "
var stringDate = " "
var stringUuid = " "
// We check for existence in the dictionnary
if (message["content"] != nil){
stringContent = message["content"] as! String
}
if (message["sender_uuid"] != nil){
stringSenderUuid = message["sender_uuid"] as! String
}
if (message["recipient_uuid"] != nil){
stringRecipientUuid = message["recipient_uuid"] as! String
}
if (message["date"] != nil){
if let result_number = message.value(forKey: "date") as? NSNumber
{
stringDate = "\(result_number)"
}
else {
stringDate = message.value(forKey: "date") as! String
}
}
if (message["uuid"] != nil){
stringUuid = message["uuid"] as! String
}
最佳答案
您可能需要将它们更改为 (message as AnyObject).value(forKey:"···")
(添加 forKey:
标签)。
你知道 message
应该是什么样的对象吗?反复将其转换为 AnyObject
很奇怪。创建一个新变量会更简洁 - let messageObject = message as AnyObject
然后调用 messageObject.value(forKey:"···")
。 (我怀疑你真的想把它转换成 Dictionary
或类似的东西,在这种情况下你可以做 messageDictionary["···"]
而不是调用 值(forKey:)
。)
此外,在 Swift 中,您可以这样做以进一步减少冗余:
if let content = messageObject.value(forKey:"content") as? String {
stringContent = content
}
关于swift - 无法使用类型为 'value' 的参数列表调用 '(String)',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42094734/