javascript - jquery - 更改 css 属性并重复

Question

我有这张 Sprite 表 http://codepen.io/benasl/pen/yabpxo我想在它结束后更改为另一个，在第二个结束后第一个需要重新开始，依此类推......我设法通过更改 css 属性来做到这一点，但现在我该怎么做他们循环？

setTimeout(function() {
  $(".kambarys2").css('display', 'block');
}, 3100);

body {
  background-color: #69e4c3;
}
.kambarys {
  background: url('http://i.imgur.com/pra08AS.jpg');
  background-repeat: no-repeat;
  position: relative;
  display: inline-block;
  width: 380px;
  height: 372px;
  top: 100px;
  left: 40%;
  animation: convejor 3s steps(76) infinite;
}
@keyframes convejor {
  from {
    background-position: 0px;
  }
  to {
    background-position: -28880px;
  }
}
.kambarys2 {
  background: url('http://i.imgur.com/TFvZvWz.jpg');
  background-repeat: no-repeat;
  position: absolute;
  display: inline-block;
  width: 380px;
  height: 372px;
  top: 108px;
  left: 40%;
  animation: convejor 3s steps(76) infinite;
  display: none;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="kambarys"></div>
<div class="kambarys2"></div>

Answer 1

• 使用数组更改背景图片:

var cnt=0,images=["http://i.imgur.com/TFvZvWz.jpg","http://i.imgur.com/pra08AS.jpg"]
setInterval(function() {
  $(".kambarys").css({"background-image":"url("+images[cnt]+")"});
  cnt++;
  if (cnt>=images.length) cnt=0;
}, 3100);

body {
  background-color: #69e4c3;
}
.kambarys {
  background: url('http://i.imgur.com/pra08AS.jpg');
  background-repeat: no-repeat;
  position: relative;
  display: inline-block;
  width: 380px;
  height: 372px;
  top: 100px;
  left: 40%;
  animation: convejor 3s steps(76) infinite;
}
@keyframes convejor {
  from {
    background-position: 0px;
  }
  to {
    background-position: -28880px;
  }
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="kambarys"></div>

• 切换两个div

var cnt=0;
setInterval(function() {
  $(".kambarys0").toggle(cnt);
  $(".kambarys1").toggle(!cnt); cnt=!cnt
}, 3100);

body {
  background-color: #69e4c3;
}
.kambarys0 {
  background: url('http://i.imgur.com/pra08AS.jpg');
  background-repeat: no-repeat;
  position: relative;
  display: inline-block;
  width: 380px;
  height: 372px;
  top: 100px;
  left: 40%;
  animation: convejor 3s steps(76) infinite;
}
.kambarys1 {
  display:none;
  background: url('http://i.imgur.com/TFvZvWz.jpg');
  background-repeat: no-repeat;
  position: relative;
  width: 380px;
  height: 372px;
  top: 100px;
  left: 40%;
  animation: convejor 3s steps(76) infinite;
}
@keyframes convejor {
  from {
    background-position: 0px;
  }
  to {
    background-position: -28880px;
  }
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="kambarys0"></div>
<div class="kambarys1"></div>

• 循环两个以上的div

var cnt = 0;
setInterval(function() {
    cnt++;  
    if (cnt >= $(".kambarys").length) cnt = 0;
    $(".kambarys").hide();
    $("#kambarys" + cnt).show();
  },
  3100);

body {
  background-color: #69e4c3;
}
.kambarys {
  position: relative;
  display: inline-block;
  width: 380px;
  height: 372px;
  top: 100px;
  left: 40%;
  animation: convejor 3s steps(76) infinite;
}
#kambarys0 {
  background: url('http://i.imgur.com/pra08AS.jpg');
  background-repeat: no-repeat;
}
#kambarys1 {
  display: none;
  background: url('http://i.imgur.com/TFvZvWz.jpg');
  background-repeat: no-repeat;
}
#kambarys2 {
  display: none;
  background: url('http://i.imgur.com/F6bNA00.jpg');
  background-repeat: no-repeat;
}


@keyframes convejor {
  from {
    background-position: 0px;
  }
  to {
    background-position: -28880px;
  }
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="kambarys" id="kambarys0"></div>
<div class="kambarys" id="kambarys1"></div>
<div class="kambarys" id="kambarys2"></div>