我有这个工作的 JQuery,它让用户选择一种颜色并更改图像 + 他/她选择的颜色的名称。我想要的是将 颜色名称 的值获取到 PHP $_POST
。我使用 data-caption 来更改颜色的名称。
这是我要获取的div,这是更改名称的占位符。
<div id="caption">Alumina Jade Metallic</div>
这是剩下的 html 代码。
<span data-src="car-color/car_AJM.jpg" data-caption="Alumina Jade Metallic"><a href="#?" class = "label" ><img src="../../thumb/th-Alumina-Jade.png"> </a></span>
<span data-src="car-color/car_B.jpg" data-caption="Black Metallic"><a href="#?" class = "label"><img src="../../thumb/th-Black.png"> </a></span>
<span data-src="car-color/car_BRM.jpg" data-caption="Blackish Red Metallic"><a href="#?" class = "label"><img src="../../thumb/th-Black-Red.png"> </a></span>
<span data-src="car-color/car_BMM.jpg" data-caption="Blue Metallic"><a href="#?"class = "label" ><img src="../../thumb/th-Blue-Metal.png"></a></span>
<span data-src="car-color/car_FW.jpg" data-caption="Freedom White"><a href="#?" class = "label"><img src="../../thumb/th-Freedom-White.png"> </a></span>
<span data-src="car-color/car_OM.jpg" data-caption="Orange Metallic"><a href="#?" class = "label"><img src="../../thumb/th-Orange-Metal.png"> </a></span>
<span data-src="car-color/car_RMM.jpg" data-caption="Red Metallic"><a href="#?"class = "label" ><img src="../../thumb/th-Red-Metal.png"> </a></span>
<span data-src="car-color/car_SM.jpg" data-caption="Silver Metallic"><a href="#?" class = "label"><img src="../../thumb/th-Silver-Metal.png"> </a></span>
<span data-src="car-color/car_WP.jpg" data-caption="White Pearl"><a href="#?"class = "label" ><img src="../../thumb/th-White-Pearl.png"> </a></span>
这是我的工作 jQuery :
$('.thumb span').each(function(){
var _this = $(this);
var src = _this.data("src");
var text = _this.data("caption");
_this.find('a').click(function(){
$("#image").show( function() {
$(".img img").attr("src", src);
$("#caption").text(text);
});
});
});
更新
这是我的 ajax 代码,用于将其传递给我的 request.php
$('.car-quote #getQuote').on('click', function(e){
e.preventDefault();
var variantOpt = $('#variantOpt').val();
var fName = $('#fName').val();
var lName = $('#lName').val();
var address = $('#address').val();
var doBirth = $('#doBirth').val();
var city = $('#city').val();
var zipCode = $('#zipCode').val();
var email = $('#email').val();
var phone = $('#phone').val();
var remarks = $('#remarks').val();
var form = new Array({ 'variantOpt':variantOpt, 'fName':fName, 'lName':lName, 'address':address, 'doBirth':doBirth, 'city':city, 'zipCode':zipCode,
'email':email, 'phone':phone, 'remarks':remarks });
$.ajax({
type: 'POST',
url: "/093017/inquiry/mailInqueries/requestaquote.php",
data: ({'action': 'car-quote', 'form': form})
}).done(function(data) {
$('#car-quote .result').html(data);
$(".car-quote")[0].reset();
});
这是在我的 request.php
$action = $_POST['action'];
$variantOpt = $_POST['form'][0]['variantOpt'];
$fName = $_POST['form'][0]['fName'];
$lName = $_POST['form'][0]['lName'];
$address = $_POST['form'][0]['address'];
$doBirth = $_POST['form'][0]['doBirth'];
$city = $_POST['form'][0]['city'];
$zipCode = $_POST['form'][0]['zipCode'];
$email = $_POST['form'][0]['email'];
$phone = $_POST['form'][0]['phone'];
$remarks = $_POST['form'][0]['remarks'];
最佳答案
使用html 获取div 的内容
var color = $('#caption').html();
关于javascript - jquery 获取表单 DIV 的数据到 PHP $_POST,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46926845/