前两个示例链接有效,第三个链接返回 NIL。
为什么 NSUrl 对于这样的字符串返回 nil,即使它在浏览器中是一个有效的 url?
我是否应该对字符串进行更多处理?
这是我的代码:
import UIKit
import Foundation
class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate, NSXMLParserDelegate {
var myFeed : NSArray = []
var url : NSURL!
var feedURL : NSURL!
var selectedFeedURL = String()
@IBOutlet var tableFeeds: UITableView!
@IBOutlet var webView: UIWebView!
override func viewDidLoad() {
super.viewDidLoad()
// Set feed url.
//url = NSURL(string: "http://www.skysports.com/rss/0,20514,11661,00.xml")! //This seems to work
//url = NSURL(string: "http://www.formula1.com/rss/news/latest.rss")! //This seems to work
url = NSURL(string: "http://www.multirotorusa.com/feed/")!
loadRss(url);
}
func loadRss(data: NSURL) {
var myParser : XmlParserManager = XmlParserManager.alloc().initWithURL(data) as XmlParserManager
myFeed = myParser.feeds
tableFeeds.reloadData()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
func numberOfSectionsInTableView(tableView: UITableView) -> Int {
return 1
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return myFeed.count
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath) as UITableViewCell
var dict : NSDictionary! = myFeed.objectAtIndex(indexPath.row) as NSDictionary
cell.textLabel?.text = myFeed.objectAtIndex(indexPath.row).objectForKey("title") as? String
cell.detailTextLabel?.text = myFeed.objectAtIndex(indexPath.row).objectForKey("description") as? String
return cell
}
func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
var indexPath: NSIndexPath = self.tableFeeds.indexPathForSelectedRow()!
var selectedFeedURL = myFeed.objectAtIndex(indexPath.row).objectForKey("link") as String
selectedFeedURL = selectedFeedURL.stringByReplacingOccurrencesOfString(" ", withString:"")
selectedFeedURL = selectedFeedURL.stringByReplacingOccurrencesOfString("\n", withString:"")
// feedURL = NSURL(fileURLWithPath: selectedFeedURL) //This returns with: URL + /%09%09 -- file:///
feedURL = NSURL(string: selectedFeedURL) //This returns with NIL
println("Selected Feed URL: \(selectedFeedURL)")
println("Feed URL: \(feedURL)")
if feedURL != nil {
let request : NSURLRequest = NSURLRequest(URL: feedURL!)
webView.loadRequest(request)
println("Feed URL: \(feedURL)") //Doesn't make it here
}
}
}
有什么建议吗?
最佳答案
您应该像这样对 URL 进行 URL 编码:
selectedFeedUrl = selectedFeedUrl.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)
关于string - SWIFT:为什么 "NSURL(string:"返回 Nil,即使它在浏览器中是有效的 url?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28304736/