我的应用程序中有一个自定义键盘扩展,它是使用 swift 开发的。他们的键盘工作正常。我想添加在长按键盘按钮(如默认 iOS 键盘)时显示带有额外字符的弹出窗口的功能。像这样:
我搜索了很多,但大多数都没有回答,回答的都在 Obj-C 中。我对 Obj-C 知之甚少,对快速编程也很陌生。
我已经看了this , this和 this .但这些都没有太大帮助。
非常感谢任何帮助。
最佳答案
<强>1。在您的 View 上添加按钮
(这只是为了向您展示)
let btn: UIButton=UIButton(frame: CGRect(x: 5, y: 70, width: 30, height: 30))
btn.setTitle("A", for: .normal)
btn.setTitleColor(UIColor.black, for: .normal);
self.view.addSubview(btn)
<强>2。在您的按钮上添加长按手势
let longGesture = UILongPressGestureRecognizer(target: self, action: #selector(longPress(sender:)))
longGesture.minimumPressDuration = 1.2
btn.addGestureRecognizer(longGesture)
<强>3。处理长按手势 ,
您可以添加 PopUpView 并在其上添加一些按钮,
⚠️ Note: You have Multiple buttons so you have to check From CGPoint on Which Button it was tapped on
func longPress( sender: Any) {
let longPressGesture = sender as! UILongPressGestureRecognizer
//Only run this code When State Begain
if longPressGesture.state != UIGestureRecognizerState.Began {
return
}
// if PopUpView is Already in added than remove and than add
if let checkView = self.view.viewWithTag(1001) as? UIView {
// remove popView
popUpView .removeFromSuperview()
}
let tapLocation = longPressGesture.location(in: self.view)
popUpView=UIView(frame: CGRect(x: tapLocation.x-10, y: tapLocation.y-65, width: 150, height: 60))
popUpView.backgroundColor=UIColor.orange
popUpView.layer.cornerRadius=5
popUpView.layer.borderWidth=2
popUpView.tag=1001
popUpView.layer.borderColor=UIColor.black.cgColor
let btn0: UIButton=UIButton(frame: CGRect(x: 5, y: 5, width: 30, height: 30))
btn0.setTitle("A1", for: .normal)
btn0.setTitleColor(UIColor.black, for: .normal);
btn0.layer.borderWidth=0.5
btn0.layer.borderColor=UIColor.lightGray.cgColor
popUpView.addSubview(btn0)
let btn1: UIButton=UIButton(frame: CGRect(x: 35, y: 5, width: 30, height: 30))
btn1.setTitle("A2", for: .normal)
btn1.setTitleColor(UIColor.black, for: .normal);
btn1.layer.borderWidth=0.5
btn1.layer.borderColor=UIColor.lightGray.cgColor
popUpView.addSubview(btn1)
let btn2: UIButton=UIButton(frame: CGRect(x: 70, y: 5, width: 30, height: 30))
btn2.setTitle("A2", for: .normal)
btn2.setTitleColor(UIColor.black, for: .normal);
btn2.layer.borderWidth=0.5
btn2.layer.borderColor=UIColor.lightGray.cgColor
popUpView.addSubview(btn2)
btn0.addTarget(self, action: #selector(self.buttonAction(sender:)),
for: UIControlEvents.touchUpInside)
btn1.addTarget(self, action: #selector(self.buttonAction(sender:)),
for: UIControlEvents.touchUpInside)
btn2.addTarget(self, action: #selector(self.buttonAction(sender:)),
for: UIControlEvents.touchUpInside)
self.view.addSubview(popUpView)
}
<强>4。处理额外的按钮按下
(在这里做你的东西添加从 SuperView 中删除 popUpView)
func buttonAction( sender: Any) {
// Do your Stuff Here
//Than remove popView
popUpView .removeFromSuperview()
}
结果 ✅
✅ Note: You can Draw custom Shape of PopUpView Using
UIBezierPath
关于ios - Swift 自定义键盘 - 在键盘长按时显示额外的字母弹出窗口?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44109200/