swift - 我可以在 Swift 的 guard 语句中使用范围运算符吗？

Question

我正在尝试寻找一种替代方法来执行此类操作，即使用范围运算符。

guard let statusCode = (response as? HTTPURLResponse)?.statusCode, statusCode >= 200 && statusCode <= 299 else {return}

也许是这样的:

guard let statusCode = (response as? HTTPURLResponse)?.statusCode where (200...299).contains(statusCode) else {return}

或

guard let statusCode = (response as? HTTPURLResponse)?.statusCode, statusCode case 200...299 else {return}

这在 Swift 中可能吗？

Answer 1

如你所愿:

guard
    let statusCode = (response as? HTTPURLResponse)?.statusCode,
    (200...299).contains(statusCode) else {return}

或:

guard
    let statusCode = (response as? HTTPURLResponse)?.statusCode,
    case 200...299 = statusCode else {return}

或:

guard
    let statusCode = (response as? HTTPURLResponse)?.statusCode,
    200...299 ~= statusCode else {return}