我正在尝试将给定的 double 转换为科学记数法,但遇到了一些问题。我似乎也找不到很多关于如何做的文档。目前我正在使用:
var val = 500
var numberFormatter = NSNumberFormatter()
numberFormatter.numberStyle = NSNumberFormatterStyle.ScientificStyle
let number = numberFormatter.numberFromString("\(val)")
println(number as Double?)
// Prints optional(500) instead of optional(5e+2)
我做错了什么?
最佳答案
您可以设置 NumberFormatter 属性 positiveFormat 和 exponent Symbol 以根据需要格式化字符串,如下所示:
let val = 500
let formatter = NumberFormatter()
formatter.numberStyle = .scientific
formatter.positiveFormat = "0.###E+0"
formatter.exponentSymbol = "e"
if let scientificFormatted = formatter.string(for: val) {
print(scientificFormatted) // "5e+2"
}
更新:Xcode 9 • Swift 4
您还可以创建扩展以从数字类型获取科学格式的描述,如下所示:
extension Formatter {
static let scientific: NumberFormatter = {
let formatter = NumberFormatter()
formatter.numberStyle = .scientific
formatter.positiveFormat = "0.###E+0"
formatter.exponentSymbol = "e"
return formatter
}()
}
extension Numeric {
var scientificFormatted: String {
return Formatter.scientific.string(for: self) ?? ""
}
}
print(500.scientificFormatted) // "5e+2"
关于ios - 快速将 Double 转换为科学记数法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31934088/