ios - 如何快速调用另一个类的另一个方法？

Question

mainController = (ViewController *)self.presentingViewController;   
mainController.pressureUnit = _pressureSettings.selectedSegmentIndex;

这就是我在 Objective C 中的做法。我如何在 swift 中做到这一点？

Answer 1

otherClass().methodFromOtherClass() 是 swift 的语法

如果您必须传递具有外部名称的属性，它可能是:

otherClass().methodFromOtherClass(propertyName: stringName)//传递字符串的例子

调用方法做某事，如果它返回方法的结果:

让 returnValue = otherClass().methodFromOtherClass(propertyName: stringName)

访问属性或函数的示例

class CarFactory { 
   var name = ""
   var color = "" 
   var horsepower = 0 
   var automaticOption = false

   func description() { 
       println("My \(name) is \(color) and has \(horsepower) horsepowers") 
   }
} 

var myCar = CarFactory() 
myFirstCar.name = "Mustang"
myCar.color = "Red"
myCar.horsepower = 200 myCar.automaticOption = true
myFirstCar.description() // $: "My Mustang is Red and has 200 horsepowers and is Automatic"

摘自:Apple Inc.“The Swift Programming Language”。电子书。

在这里你只是调用方法而不是类的新实例。

class SomeClass {
    class func someTypeMethod() {
        // type method implementation goes here
    }
}

SomeClass.someTypeMethod()