当我的应用捕捉到远程通知时，我尝试打开一个特定的 ViewController。
让我展示一下我的项目架构。
这是我的 Storyboard:
当我收到通知时，我想打开一个“SimplePostViewController”，所以这是我的 appDelegate:
var window: UIWindow?
var navigationVC: UINavigationController?
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
let notificationTypes: UIUserNotificationType = [UIUserNotificationType.Alert, UIUserNotificationType.Badge, UIUserNotificationType.Sound]
let pushNotificationSettings = UIUserNotificationSettings(forTypes: notificationTypes, categories: nil)
let storyboard = UIStoryboard(name: "Main", bundle: nil)
self.navigationVC = storyboard.instantiateViewControllerWithIdentifier("LastestPostsNavigationController") as? UINavigationController
application.registerUserNotificationSettings(pushNotificationSettings)
application.registerForRemoteNotifications()
return true
}
func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) {
if let postId = userInfo["postId"] as? String {
print(postId)
let api = EVWordPressAPI(wordpressOauth2Settings: Wordpress.wordpressOauth2Settings, site: Wordpress.siteName)
api.postById(postId) { post in
if (post != nil) {
self.navigationVC!.pushViewController(SimplePostViewController(), animated: true)
} else {
print("An error occurred")
}
}
}
}
我在应用程序启动时保存我的 UINavigationViewController，并在收到通知时尝试推送一个新的 SimplePostViewController。但什么也没有发生。 我放置了断点，看到到达了我的 pushViewController 方法，但没有到达我的 SimplePostViewController 的 ViewWillAppear。
我还使用了“新增功能” View 添加执行我的 segue 但也没有任何反应。
解决方案:
for child in (self.rootViewController?.childViewControllers)! {
if child.restorationIdentifier == "LastestPostsNavigationController" {
let lastestPostsTableViewController = (child.childViewControllers[0]) as! LastestPostsTableViewController
let simplePostVC = (self.storyboard?.instantiateViewControllerWithIdentifier("PostViewController"))! as! PostViewController
simplePostVC.post = post
lastestPostsTableViewController.navigationController?.pushViewController(simplePostVC, animated: true)
}
}
我用:
child.childViewControllers[0]
因为我的示例中只有一个 child 。
最佳答案
我创建了一个带有本地通知而不是远程通知的示例项目，以便于显示功能，但它应该像在应用程序委托(delegate)中设置窗口的 Root View Controller 一样简单 didreciveremote 通知。
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
// Subscribe for notifications - assume the user chose yes for now
application.registerUserNotificationSettings(UIUserNotificationSettings(forTypes: [.Alert, .Badge, .Sound], categories: nil))
return true
}
func applicationDidEnterBackground(application: UIApplication) {
//Crete a local notification
let notification = UILocalNotification()
notification.alertBody = "This is a fake notification"
notification.fireDate = NSDate(timeIntervalSinceNow: 2)
UIApplication.sharedApplication().scheduleLocalNotification(notification)
}
func application(application: UIApplication, didReceiveLocalNotification notification: UILocalNotification) {
let sb = UIStoryboard(name: "Main", bundle: nil)
let otherVC = sb.instantiateViewControllerWithIdentifier("otherVC") as! OtherViewController
window?.rootViewController = otherVC;
}
func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) {
//Your code here
}
` 您需要担心管理您的 View 层次结构并向它发送您需要从通知用户数据发送的任何内容。
在我的示例中，我创建了一个本地通知，当您关闭在查看几秒后触发的应用程序时。如果您随后从通知启动该应用程序，它将打开“其他 View Controller ”，在您的情况下这将是“SimplePostViewController”。
此外，请确保您在 didFinishLaunchWithOptions 中注册了远程通知。
Github 非常简单的示例:https://github.com/spt131/exampleNotificationResponse
关于swift - 从远程通知打开 ViewController，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39112114/