c++ - 使用 Structs 作为映射中的键，忽略 == 运算符，误报

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我正在尝试将结构用作映射中的键，但尽管定义了 <和 ==运营商我收到误报:

return models[mr];即使新的 ImportSettings 也正在返回有reverse = true模型中的那个有`reverse = false。

Visual Studio 调试器还显示运算符调用了 ==甚至没有被调用。我在这里误解了什么？

struct HE2_ImportSettings
{
    bool reverseWindingOrder = false;

    bool operator==(const HE2_ImportSettings& other)const
    {
        return reverseWindingOrder == other.reverseWindingOrder;
    }
};

struct ModelReference
{
    std::string filepath = "";
    HE2_ImportSettings importSettings = {};

    bool ModelReference::operator == (const ModelReference& other) const
    {
        return filepath == other.filepath && importSettings == other.importSettings;
    }
    bool ModelReference::operator< (const ModelReference& other) const
    {
        return filepath < other.filepath;
    }
};



ModelReference mr = { filename, importSettings };

bool exists = models.count(mr);
if (exists)
{
    //This is returning even when the new importsettings has reverse = true and the one in models has reverse = false
    return models[mr];
}

最佳答案

std::map使用等效的概念。

时两个元素是等价的