我有以下关系和
1.我想找到每个供应商提供的零件的pid,并且小于200。 (如果任何供应商要么不简单的部分或收取超过 200 的部分,则不选择该部分)
fiddle http://sqlfiddle.com/#!2/4b5d4
Supplies
sid 1 2 3 4 5
sname Jason David John Peter Jay
address 221 2b 3c 4d 5e
Parts
pid 10 20 30 40 50 60
pname Head Body Hand Leg Arm Foot
color red blue green white red green
Catalog
sid 1 1 2 2 3 4 1 1 4 4 1 5 5 3 3 2
pid 10 20 20 30 30 40 30 40 10 50 50 50 10 60 10 10
cost 150 220 150 150 130 125 130 280 123 126 120 100 100 210 100 50
所以我做了以下查询
我认为这等于没有供应商不提供的零件。
SELECT C.pid
FROM CATALOG C
WHERE C.cost < 200
AND NOT EXISTS (SELECT S.sid
FROM Suppliers S
WHERE NOT EXISTS
(SELECT P.pid
FROM Parts P
WHERE P.pid = C.pid
AND S.sid = C.sid ))
但它返回 null,它应该返回 10。
2.我想为每个提供绿色部件和红色部件的供应商找到她提供的最昂贵部件的名称和价格。
我只能找出绿色和红色部分,但找不到最贵的部分。
查询是我试过的
SELECT S.sname
FROM Suppliers AS S,
Parts AS P1,
CATALOG AS C1,
Parts AS P2 ,
CATALOG AS C2
WHERE S.sid = C1.sid
AND C1.pid = P1.pid
AND S.sid = C2.sid
AND C2.pid = P2.pid
AND ( P1.color = 'red'
AND P2.color = 'green' )
我该如何解决?提前致谢。
ps抱歉,我要去上课了,我会在大约6小时后回复。
最佳答案
第一部分
从目录中选择 pid where cost<200 group by pid having count(Sid)>=(Select Count(sid) from Suppliers)
第二部分-:
Select t.sname,Max(Catalog.cost) from (SELECT S.sname,c2.cost,c2.sid
FROM Suppliers AS S, Parts AS P1, Catalog AS C1, Parts AS P2 , Catalog AS C2
WHERE S.sid = C1.sid
AND C1.pid = P1.pid
AND S.sid = C2.sid
AND C2.pid = P2.pid
AND (
P1.color = 'red'
AND P2.color = 'green'
) ) t inner join Catalog on t.sid =Catalog.sid
group by t.sid
关于mysql - 在某种条件下找到每件元素和最昂贵的元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16455166/