$cteachers = mysql_query("SELECT * FROM teachers WHERE teachers.stats = '1'") or die(mysql_error());
while($info = mysql_fetch_array( $cteachers ))
{
Print "<li><strong>$info['id'];</strong></li><li><strong>$info['name'];</strong></li>"<li><strong>$info['rnk'];</strong></li>;
$id = $info['id'];
$cnme = $info['name'];
$fnme = $info['f_name'];
$lnme = $info['l_name'];
$rnkk = $info['rnk'];
$fullname = $fnme." ".$lnme;
if ($cnme == '')
{
$que2 = "UPDATE teachers (name) VALUES('$fullname') WHERE teachers.f_name = '"$fnme"' AND teachers.l_name = '"$lnme"'" or die(mysql_error());
$exe2 = mysql_query($que2) or die(mysql_error());
}
你好，我遇到了一个问题，请帮助我，它将提供教师的完整列表，但如果教师全名字段为空，请更新它
最佳答案
为什么不在一条 SQL 中完成呢？
UPDATE teachers
SET name = CONCAT(f_name, " ", l_name)
WHERE stats = "1"
AND name = ""
(将 name = "" 更改为 name IS NULL 如果它是一个可为空的字段)
关于php - 如何在 while 循环期间通过 if 条件更新表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/17498191/