MySQL join 两个独立的查询结果

Question

我有两个不同的查询，例如

// This query will return past month records
SELECT b.list_id, r.name, r.city, FROM_UNIXTIME(b.bookingdate, '%Y-%m-%d- %h:%i:%s') AS 'bookingdate', COUNT(*) AS bookings
FROM booking b JOIN restaurants r ON r.list_id = b.list_id
WHERE b.bookingdate BETWEEN 1383224400 AND 1385730000 GROUP BY b.list_id

// This query will return current month records
SELECT b.list_id, r.name, r.city, FROM_UNIXTIME(b.bookingdate, '%Y-%m-%d- %h:%i:%s') AS 'bookingdate', COUNT(*) AS bookings
FROM booking b JOIN restaurants r ON r.list_id = b.list_id
WHERE b.bookingdate BETWEEN 1385816400 AND 1388408400 GROUP BY b.list_id

两个查询的结果字段 list_id、姓名、城市、预订日期、预订

我想将两个查询结果合并为一个，并希望结果字段像 list_id、姓名、城市、预订日期、bookings_lastmonth、bookings_currentmonth

执行此操作的最佳方法是什么？

Answer 1

使用 UNION 属性:-

SELECT b.list_id, r.name, r.city, FROM_UNIXTIME(b.bookingdate, '%Y-%m-%d- %h:%i:%s') AS 'bookingpreviousdate', '0' AS bookingnextdate, COUNT(*) AS bookings
FROM booking b JOIN restaurants r ON r.list_id = b.list_id
WHERE b.bookingdate BETWEEN 1383224400 AND 1385730000 GROUP BY b.list_id
UNION
SELECT b.list_id, r.name, r.city, '0' AS 'bookingpreviousdate', 'FROM_UNIXTIME(b.bookingdate, '%Y-%m-%d- %h:%i:%s')' AS bookingnextdate, COUNT(*) AS bookings
FROM booking b JOIN restaurants r ON r.list_id = b.list_id
WHERE b.bookingdate BETWEEN 1385816400 AND 1388408400 GROUP BY b.list_id