这是我的查询，我正在尝试使用另一个表中的数字从另一个表中获取数字这是我的查询...
$order_id = $template_vars['{order_name}'];
// Query to find the product id for the current order and then set it to a variable
$query="SELECT product_id FROM ps_order_detail WHERE id_order = $order_id";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
$Product_id = $row['0'];
// get all the custom part numbers and set them to the variables
$customnumbers ="SELECT API, SWAIM, JOHN_CRANE, SNOW_WELL, MIDAS, QUINN, WILSON, WEATHERFORD, HF, BLACK_GOLD, EDI, SO_CAL_PUMPS, WEST_RIVER
FROM ps_product_part_number WHERE Product_ID = $Product_id";
$secondresult = mysql_query($customnumbers);
$secondrow = mysql_fetch_row($secondresult);
$API = $secondrow['0'];
$SWAIM = $secondrow['1'];
$JOHN_CRANE = $secondrow['2'];
$SNOW_WELL = $secondrow['3'];
$MIDAS = $secondrow['4'];
$QUINN = $secondrow['5'];
$WILSON = $secondrow['6'];
$WEATHERFORD = $secondrow['7'];
$HF = $secondrow['8'];
$BLACK_GOLD = $secondrow['9'];
$EDI = $secondrow['10'];
$SO_CAL_PUMPS = $secondrow['11'];
$WEST_RIVER = $secondrow['12'];
最佳答案
通过连接一步完成如何？
SELECT ppn.*
FROM ps_product_part_number ppn
join ps_order_detail od on od.product_id = ppn.Product_ID
WHERE od.id_order = $order_id
关于php - 查询错误得不到数字，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22519497/