php - 选择 MySQL 范围内的所有时间戳

Question

我正在为我的项目开发类似日历的功能。

我有如下表格:

ID | Title             |Where     |tri| Start      | End        | tro
______________________________________________________________________
"4"|"Planingfrenzy"    |"Street 8"|"0"|"1395835200"|"1395846000"|"1"
"5"|"Other meeting"    |"Road 8"  |"0"|"1395140400"|"1395158400"|"1"
"6"|"Third meeting"    |"Lane 8"  |"0"|"1395819000"|"1395824400"|"1"
"8"|"Weekend at cyprus"|"Cyprus"  |"0"|"1395928800"|"1396162800"|"1"

我在选择一天内发生的所有事件时遇到问题。 我尝试了以下两个查询，但它们只返回那些在同一天开始和结束的事件。

/*
   Start is a unixtimestamp for the beginning of the day
   End is a unixtimestamp for the end of the day
*/

//This Returns to many events since all events that ends before the end timestamp is a match etc. 
SELECT * FROM events WHERE (start > ? OR end<?) 

//This matches all events that start and end at the same day. But a multi day event like "Weekend at cyprus" isn't returned since it is out of range
SELECT * FROM events WHERE (start > ? AND end<?)

如果开始/结束范围“触及”查询的时间戳范围，MySQL 或 PHP 是否有某种方法可以匹配？

Answer 1

假设?的两个值是当天最早和最新的值，我想你想要:

where start < (?end) and end > (?start)

也就是说，当一个开始在另一个结束之前时存在重叠，反之亦然。

在这个答案中，(?end) 是当天的最后一个时间戳，(?start) 是第一个。