我想按用户 ID 列出数据库中的每个产品以及访问者跟踪和销售信息。
这是我目前得到的:
http://www.sqlfiddle.com/#!2/ec506/19
SELECT products.product_name,
tracking.unique_hits,
tracking.total_hits,
COUNT(sales.product_id) as total_sales,
SUM(sales.amount) as total_revenue
FROM products
INNER JOIN tracking ON products.id = tracking.product_id
INNER JOIN sales ON products.id = sales.product_id
WHERE products.vendor_id = 0;
它输出这个:
| PRODUCT_NAME | UNIQUE_HITS | TOTAL_HITS | TOTAL_SALES | TOTAL_REVENUE |
|----------------|-------------|------------|-------------|---------------|
| test product 1 | 42 | 52 | 3 | 30 |
但我希望它也输出没有销售的产品,所以它应该输出这样的东西:
| PRODUCT_NAME | UNIQUE_HITS | TOTAL_HITS | TOTAL_SALES | TOTAL_REVENUE |
|----------------|-------------|------------|-------------|---------------|
| test product 1 | 42 | 52 | 3 | 30 |
| test product 2 | 10 | 13 | 0 | 0 |
或者
| PRODUCT_NAME | UNIQUE_HITS | TOTAL_HITS | TOTAL_SALES | TOTAL_REVENUE |
|----------------|-------------|------------|-------------|---------------|
| test product 1 | 42 | 52 | 3 | 30 |
| test product 2 | 0 | 0 | 0 | 0 |
如果表中甚至没有访问者跟踪数据。
我不知道该怎么做。需要一些帮助! :)
最佳答案
只需切换到左外连接
:
SELECT products.product_name,
tracking.unique_hits,
tracking.total_hits,
COUNT(sales.product_id) as total_sales,
coalesce(SUM(sales.amount), 0) as total_revenue
FROM products
LEFT OUTER JOIN tracking ON products.id = tracking.product_id
LEFT OUTER JOIN sales ON products.id = sales.product_id
WHERE products.vendor_id = 0
GROUP BY products.product_name, tracking.unique_hits, tracking.total_hits;
编辑:
感谢 M Khalid 提供的group by
。我会用表别名编写此查询以使其更易于阅读:
SELECT p.product_name, t.unique_hits, t.total_hits,
COUNT(s.product_id) as total_sales,
coalesce(SUM(s.amount), 0) as total_revenue
FROM products p LEFT OUTER JOIN
tracking t
ON p.id = t.product_id LEFT OUTER JOIN
sales s
ON p.id = s.product_id
WHERE p.vendor_id = 0
GROUP BY p.product_name, t.unique_hits, t.total_hits;
关于MySql 查询连接 3 个空行的表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23278580/