我有一个名为 tuition
的表
我想检索所有学习 111
和不学习 333
的学生
这是我能想到的:
http://www.sqlfiddle.com/#!2/f6411/3
stud_id | subject_id
--------------------
1 111
1 222
2 222
2 333
3 111
3 222
3 333
4 111
4 222
输出:
stud_id
-------
1
4
最佳答案
三种选择:
使用
HAVING
子句和WHERE
子句:SELECT * FROM tution WHERE subject_id = 111 OR subject_id=333 GROUP BY stud_id HAVING COUNT(DISTINCT subject_id)=1 AND subject_id<>333
结果为 SQL Fiddle .
使用不带
WHERE
子句的HAVING
子句:SELECT * FROM tution GROUP BY stud_id HAVING COUNT(DISTINCT subject_id)=2 AND subject_id =111 AND subject_id<>333
结果为 SQL Fiddle .
使用
IN
:SELECT * FROM tution WHERE subject_id=111 AND stud_id NOT IN (SELECT stud_id FROM tution WHERE subject_id= 333)
结果为 SQL Fiddle .
结果:
STUD_ID SUBJECT_ID
1 111
4 111
关于mysql - 检索满足一个条件但不满足另一个条件的记录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23671534/