我有两个表:
table1:
id
--
1
2
3
table2: (left out primary index)
id2 | cond
----------
3 | 1
3 | 0
2 | 1
2 | 1
2 | 0
我需要构造一个隐式计算此中间表的查询:
temp:
id | c1 | c2
------------
1 | 0 | 2
2 | 2 | 2
3 | 1 | 2
与 c1 = countRows(id2 == id && cone == 1)
和 c2 == countRows(id2 = 2 && cond == 1)
.
然后选择 SELECT id FROM temp ORDER BY ABS(c1 - c2)*RAND()
.
我目前的尝试是这样的:
SELECT id, COUNT(t1.id2) AS c1, COUNT(t2.id2) AS c2
FROM table1 LEFT JOIN (table2 AS t1) ON id=t1.id2 LEFT JOIN (table2 AS t2) ON t2.id2=2
WHERE t1.cond=1 AND t2.cond=1
GROUP BY t1.id2
ORDER BY ABS(c1 - c2)*RAND()
LIMIT 1
其中有多个问题:
- 它不会选择表 2 中没有条目的行
- 计算不正确
- ORDER BY 第 3 部分中的组列 (c1, c2) 似乎有问题。
帮助将不胜感激。
更新:
- table1代表玩家,例如
- table2 将进行几轮比赛,cond 表示获胜
- c1代表每个玩家赢得的回合数
- c2 代表引用玩家(在本例中为玩家 2)赢得的回合数
最佳答案
SELECT t1.id, SUM(IFNULL(t2.cond, 0) = 1) AS c1, (SELECT SUM(cond = 1) FROM table2 WHERE id2 = 2) AS c2
FROM table1 t1
LEFT JOIN table2 t2 ON t1.id = t2.id2
GROUP BY t1.id
ORDER BY ABS(SUM(IFNULL(t2.cond, 0) = 1) - c2) * RAND();
关于mysql - 对两个表的复杂查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24111836/