我需要合并 3 个求和查询的结果并在循环中回显结果。我坚持如何以正确的方式完成这项工作。我想使用 while 循环为每个客户端回显一行,显示按客户端名称分组的 3 个总和查询的结果:
客户名称 |总到期 |现金销售应付总额 |赊销应收总额
结果显示全部归功于客户。 noncashresult 显示所有来自 Credit sales 的客户。 cashresult 显示现金销售中所有应收给客户的款项。
$result = mysql_query("SELECT `client_name` As `Client`, SUM(`due_to_client`) As `Total Due`
FROM `Consignment`
WHERE `payout_approved` = 'Yes'
GROUP BY `client_name`");
$noncashresult = mysql_query("SELECT `client_name` As `Client`, SUM(`due_to_client`) As `Credit Total Due`
FROM `Consignment`
WHERE `payout_approved` = 'Yes' AND `paymenttype` IN ('Credit')
GROUP BY `client_name`");
$cashresult = mysql_query("SELECT `client_name` As `Client`, SUM(`due_to_client`) As `Cash Total Due`
FROM `Consignment`
WHERE `payout_approved` = 'Yes' AND `paymenttype` IN ('Cash')
GROUP BY `client_name`");
while($row = mysql_fetch_array($result))
{
echo $row['Client'];
echo $row['Total Due'];
echo $row['Credit Total Due'];
echo $row['Cash Total Due'];
}
最佳答案
你可以使用类似的东西:
SELECT `client_name` As `Client`,
SUM(`due_to_client`) As `Total Due`,
SUM(CASE WHEN `paymenttype`='Credit' THEN `due_to_client` ELSE 0 END) As `Credit Total Due`,
SUM(CASE WHEN `paymenttype`='Cash' THEN `due_to_client` ELSE 0 END) As `Cash Total Due`
FROM `Consignment`
WHERE `payout_approved` = 'Yes'
GROUP BY `client_name`
这应该产生结果:
Client | Total Due | Credit Total Due | Cash Total Due
当然,尽量避免使用 mysql_* 扩展名,而这在 mysql 5.5.x 中已被弃用。而是使用 mysqli 或 pdo 扩展
关于php - 使用 Union 或 Join 在一个 where 语句中使用多个查询结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24768988/