以下代码完美运行。它给出预订 ID RRGPGM68
hotel url
<?PHP
$con=mysqli_connect("localhost","username","pasword","dbName");
// Check connection
if (mysqli_connect_errno()) {
die ("Failed to connect to MySQL: " . mysqli_connect_error());
}
$booking_id_serch_text = RRGPGM68;
$searchroute = "select * from booking_tbl where booking_nmbr = '$booking_id_serch_text'";
$result = $con->query($searchroute);
$row = $result->fetch_assoc();
echo 'Hotel URL: '.$row['hotel_url'];
mysqli_close($con);
?>
但我想从文本输入字段中动态分配 booking_id_serch_text
。所以我修改了代码如下:
<form action="<?php echo get_permalink();?>" method="post">
<input type="text" placeholder="Search..." required name="search_text">
<input type="button" value="search" name="search">
</form>
<?PHP
if($_POST["search"]){
$serch_text = $_POST["search_text"];
$con=mysqli_connect("localhost","username","pasword","dbName");
// Check connection
if (mysqli_connect_errno()) {
die ("Failed to connect to MySQL: " . mysqli_connect_error());
}
$booking_id_serch_text = $serch_text;
$searchroute = "select * from booking_tbl where booking_nmbr = '$booking_id_serch_text'";
$result = $con->query($searchroute);
$row = $result->fetch_assoc();
echo 'Hotel URL: '.$row['hotel_url'];
mysqli_close($con);
}
?>
但是上面的代码什么也没做。 我怎样才能让它发挥作用? 此用途存档后,我将添加验证。
最佳答案
<input type="button" /> buttons
不会提交表单——默认情况下他们什么都不做。它们通常作为 AJAX 应用程序的一部分与 JavaScript 结合使用。
<input type="submit"> buttons
将在用户点击它们时提交它们所在的表单,除非您使用 JavaScript 另行指定。
所以在这里使用
关于php - 如何使用 mySql 唯一 ID/列名称搜索记录?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25929520/