javascript - 获取单选按钮值(PhP MySQL 和 ajax)

Question

这里是新手.. 我有这段代码用于在表格中显示数据库记录， 我想知道如何获取单选按钮的值(单选按钮包含所选行的 ID)。我试着用 javascript 做，但没有成功。

表格.php

<table border="1">
    <th></th>
    <th>Particulars</th>
    <th>Amount</th>

        <?php
            include('includes/config.php');
            $qry = $con->prepare('SELECT * FROM fees');
            $qry->execute();
            $row = $qry->rowCount();

            while ($row = $qry->fetch(PDO::FETCH_ASSOC)) {
                $id = $row['fee_id'];
                $fee = $row['fee_name'];
                $amt = $row['amount'];                      
        ?>
        <?php echo "

        <tr title='Click to edit or delete record'>
           <td><input type = 'radio' name = 'radio' class ='radio' value = $row[fee_id]></td>
           <td>$fee</td>
           <td>$amt</td>                            
        </tr>

        "; ?>
        <?php } ?>      
</table>
<input type="button" value="Delete Selected Fee" style="width:250px; height:40px;font-weight:bold;" onclick="delete();"><br><br>

javascript代码

<script type="text/javascript">
        function delete(){
        if (document.getElementsByClassName(this.class).checked){
            var val = document.getElementsByClassName(this.class).value;
            alert (val);
            }
        }

</script>

Answer 1

使用这个

function delete(){
    if($('input[name="radio"]').is(':checked')){
    var val = $('input[name="radio"]').val();
    console.log(val);
    }
    }