Mysql 查询在 phpmyadmin 中显示错误

Question

我正在尝试找出具有短代码的页面 ID。这是我试图在 mysql phpmyadmin

中运行的查询

SELECT ID FROM wp_posts WHERE post_type = "page" AND post_status="publish" AND post_content LIKE "%[registration id="17"]%"

但是显示如下错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '17"]%"

在第 1 行限制 0、25'

提前致谢。

Answer 1

你的sql有问题

SELECT ID FROM wp_posts WHERE post_type = "page" AND 
post_status="publish" AND post_content LIKE "%[registration id="17"]%"
                                                               ^^^^^^

在 where like 部分使用 ' 而不是 "。

SELECT ID FROM wp_posts WHERE post_type = "page" AND 
post_status="publish" AND post_content LIKE "%[registration id='17']%"

如果你真的想匹配 注册id="17"，尝试转义"。

SELECT ID FROM wp_posts WHERE post_type = "page" AND 
post_status="publish" AND post_content LIKE "%[registration id=\"17\"]%"

或

SELECT ID FROM wp_posts WHERE post_type = "page" AND 
post_status="publish" AND post_content LIKE '%[registration id="17"]%'