mysql - 如何为列设置优先级并按该优先级对结果进行排序？

Question

我有一个这样的表:

// mytable
+----+---------+-------------------------------+
| id |   title |           content             |
+----+---------+-------------------------------+
| 1  |  hello  |  how are you?                 |
| 2  |  you    |  it is  content2              |
| 3  |  what   |  hello is a word for greating |
| 4  |  mouse  |  it is content4               |
+----+---------+-------------------------------+

嗯，我想给 title 一个比 content 更高的优先级。我的意思是，我想显示 title 列(第一个)的所有结果，然后显示 content 列(第二个)的所有结果。这也是我的查询:

select * from mytable where match(title, content) against($word);

这里还有两个例子:

示例 1:

$word = 'you';

我想要这样的输出:(关注排序)

+----+---------+-------------------------------+
| id |   title |           content             |
+----+---------+-------------------------------+
| 2  |  you    |  it is  content2              |
| 1  |  hello  |  how are you?                 |
+----+---------+-------------------------------+

示例 2:

$word = 'hello';

我想要这样的输出:(关注排序)

+----+---------+-------------------------------+
| id |   title |           content             |
+----+---------+-------------------------------+
| 1  |  hello  |  how are you?                 |
| 3  |  what   |  hello is a word for greating |
+----+---------+-------------------------------+

我再次强调，我想要所有来自 title 列的结果，然后所有来自 content 列的结果。有什么解决办法吗？

Answer 1

您需要做的就是使用 CASE 和单词匹配项进行条件排序。这是一个让你继续前进的例子

SELECT title, content
FROM tablename
ORDER BY CASE
    WHEN title LIKE '%you%' THEN 1
    WHEN content LIKE '%you%' THEN 2
    ELSE 3
END;

FIDDLE EXAMPLE