MySQL 查询不显示重复的 id

Question

如果我的查询中重复的 id_customer 是，我想不显示，

SELECT
    ps_orders.id_customer,
    ps_customer.firstname,
    ps_customer.lastname,
    ps_customer.email,
    ps_orders.total_paid
FROM
    ps_orders
    RIGHT JOIN ps_customer 
        on ps_orders.id_customer = ps_customer.id_customer
WHERE
    ps_orders.total_paid > 1
GROUP BY
    ps_orders.id_customer;

我正在使用“分组依据”来做，但它没有显示。我希望它不会显示任何内容，即使是分组依据

显示是这样的

 id_customer    firstname   lastname    email   total_paid
--------------------------------------------------------
55  name8   name10  ***@windowslive.com 88.90
58  name6   name7   ****@hotmail.com    78.90
59  name3   name5   ****@hotmail.com    123.83
60  name    name2   ****@hotmail.com    78.90

第一次查询是这样的，

SELECT
    ps_orders.id_customer,
    ps_customer.firstname,
    ps_customer.lastname,
    ps_customer.email,
    ps_orders.total_paid
FROM
    ps_orders
    RIGHT JOIN ps_customer 
        on ps_orders.id_customer = ps_customer.id_customer
WHERE
    ps_orders.total_paid > 1
ORDER BY
    ps_orders.id_customer;

没有分组依据

 id_customer    firstname   lastname    email   total_paid
--------------------------------------------------------
55  name8   name10  ***@windowslive.com 88.90
58  name6   name7   ****@hotmail.com    56.00
58  name6   name7   ****@hotmail.com    87.90
58  name6   name7   ****@hotmail.com    79.99
58  name6   name7   ****@hotmail.com    78.90
59  name3   name5   ****@hotmail.com    123.83
60  name    name2   ****@hotmail.com    78.90

但我想这样看

 id_customer    firstname   lastname    email   total_paid
--------------------------------------------------------
55  name8   name10  ***@windowslive.com 88.90
59  name3   name5   ****@hotmail.com    123.83
60  name    name2   ****@hotmail.com    78.90

Answer 1

试试这个:

SELECT
    ps_orders.id_customer,
    ps_customer.firstname,
    ps_customer.lastname,
    ps_customer.email,
    ps_orders.total_paid
FROM
    ps_orders
    JOIN ps_customer 
        on ps_orders.id_customer = ps_customer.id_customer
WHERE
    ps_orders.total_paid > 1
    AND ps_orders.id_customer IN (  SELECT  ps_orders.id_customer
                                    FROM    ps_orders
                                    GROUP BY ps_orders.id_customer
                                    HAVING COUNT(1) < 2 )