我有一个表格,我可以从中获取一些不同的信息。但是后来我有一个带有多个选项的 Select,我希望能够以 1 或 0/true 或 false 的形式将其发送到数据库。但它不起作用。到目前为止,这是我的代码:
<select name="multipleSelect[]" multiple>
<option value="" disabled selected>Choose your option</option>
<option name="esea" value="esea">ESEA</option>
<option name="faceit" value="faceit">FaceIT</option>
<option name="matchmaking" value="matchmaking">Matchmaking</option>
</select>
<label>What are you looking to play?</label>
这是我的 php:
$esea = 0;
$faceit = 0;
$matchmaking = 0;
foreach ( $_POST['multipleSelect'] as $value ) {
if ( $value == 'esea' ) { $esea = 1; }
if ( $value == 'faceit' ) { $faceit= 1; }
if ( $value == 'matchmaking' ) { $matchmaking= 1; }
}
// Sätt in dataN
$sql = "INSERT INTO users ( steamid, profilename, profileurl, avatar, region, age, ranks, esea, faceit, matchmaking, textarea1 ) VALUES (
'{$mysqli->real_escape_string($_POST['steamid'])}',
'{$mysqli->real_escape_string($_POST['profilename'])}',
'{$mysqli->real_escape_string($_POST['profileurl'])}',
'{$mysqli->real_escape_string($_POST['avatar'])}',
'{$mysqli->real_escape_string($_POST['region'])}',
'{$mysqli->real_escape_string($_POST['age'])}',
'{$mysqli->real_escape_string($_POST['ranks'])}',
$esea,
$faceit,
$matchmaking',
'{$mysqli->real_escape_string($_POST['textarea1'])}')";
$insert = $mysqli->query($sql);
我知道这段代码不起作用,但我不知道该怎么做才能让它起作用。我不想发送 1 或 0,具体取决于是否选择了替代方案。
最佳答案
您的 select
html 标记需要有一个 name
属性,以便表单 onSubmit 发送到“后端”。
像这样:
<select name="enterNameThatMakesSense" multiple> // <----- HERE
<option value="" disabled selected>Choose your option</option>
<option name="esea" value="1">ESEA</option>
<option name="faceit" value="1">FaceIT</option>
<option name="matchmaking" value="1">Matchmaking</option>
</select>
<label>What are you looking to play?</label>
关于php - 使用 POST 从 HTML 表单中获取选择选项值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36728701/