我已经用 php 和 mysql 制作了一个注册表。只有在每次都引入不同的用户名时它才有效。我怎样才能解决这个问题？因为有时我想在数据库中插入相同的名称。
我的代码:
require('connect.php');
if (isset($_POST['adresa'])) {
$username = $_POST['username'];
$email = $_POST['email'];
$adresa = $_POST['adresa'];
$judet = $_POST['judet'];
$telefon = $_POST['telefon'];
$localitate = $_POST['localitate'];
$bon = $_POST['bon'];
$date = $_POST['date'];
$premiu = $_POST['premiu'];
$query = "INSERT INTO user (username, adresa, email,judet,telefon,localitate,bon,date,premiu,acord) VALUES ('$username', '$adresa', '$email','$judet','$telefon','$localitate','$bon','$date','$premiu','$acord')";
$result = mysql_query($query);
}
最佳答案
用于检查用户名是否存在
<?php
require('connect.php');
if (isset($_POST['adresa'])) {
$username = $_POST['username'];
$email = $_POST['email'];
$adresa = $_POST['adresa'];
$judet = $_POST['judet'];
$telefon = $_POST['telefon'];
$localitate = $_POST['localitate'];
$bon = $_POST['bon'];
$date = $_POST['date'];
$premiu = $_POST['premiu'];
$chk_query = mysql_query("Select (username) from user where username=$username");
$num = mysql_num_rows($chk_query);
if($num < 1)
{
$query = "INSERT INTO user (username, adresa, email,judet,telefon,localitate,bon,date,premiu,acord) VALUES ('$username', '$adresa', '$email','$judet','$telefon','$localitate','$bon','$date','$premiu','$acord')";
$result = mysql_query($query);
}
else { echo "User name exist"; }
}
?>
关于PHP注册表格与mysql，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36911562/