我使用 MySQL。我有以下格式的数据 -
DATE , PAGE , PAGE_LOAD_DURATION , VISIT_TYPE
01-01-15 , A , 6 , AM
01-01-15 , B , 4 , PM
01-01-15 , C , 5 , AM
01-01-15 , D , 4 , AM
02-01-15 , B , 13 , PM
03-01-15 , C , 15 , PM
04-01-15 , A , 17 , PM
05-01-15 , A , 34 , PM
06-01-15 , B , 56 , AM
07-01-15 , C , 12 , AM
08-01-15 , D , 89 , AM
09-01-15 , B , 34 , AM
10-01-15 , R , 12 , PM
11-01-15 , T , 56 , AM
12-01-15 , E , 78 , PM
13-01-15 , B , 90 , AM
14-01-15 , A , 34 , PM
15-01-15 , A , 56 , AM
16-01-15 , B , 23 , AM
17-01-15 , A , 15 , PM
18-01-15 , R , 17 , AM
19-01-15 , Y , 37 , PM
20-01-15 , C , 23 , AM
我正在尝试生成给定日期范围内每种访问类型每页的平均页面加载持续时间
我想生成以下格式的输出 -
PAGE, VISIT_TYPE, AVERAGE_PAGE_LOAD_DUR
A, AM, average_page_load_dur
A, PM, average_page_load_dur
B, AM, average_page_load_dur
B, PM, average_page_load_dur
C, AM, average_page_load_dur
C, PM, average_page_load_dur
D, AM, average_page_load_dur
D, PM, average_page_load_dur
so on
要计算 SUM 而不是平均值,我使用以下查询 -
select
PAGE,
SUM(IF(VISIT_TYPE = 'AM',AVERAGE_PAGE_LOAD_DUR,0)) AS SUM_AM,
SUM(IF(VISIT_TYPE = 'PM',AVERAGE_PAGE_LOAD_DUR,0)) AS SUM_PM
from
PAGE_VISITS
where
DATE >= '01-01-15' and DATE <= '09-01-15'
group by
PAGE
为了计算平均值,我用 AVG 替换了 SUM,但是,看起来这不是正确的方法,因为在扫描每一行时计算平均值,这没有意义(这就是我的想法有效。如果不正确,请纠正我)
select
PAGE,
AVG(IF(VISIT_TYPE = 'AM',AVERAGE_PAGE_LOAD_DUR,0)) AS SUM_AM,
AVG(IF(VISIT_TYPE = 'PM',AVERAGE_PAGE_LOAD_DUR,0)) AS SUM_PM
from
PAGE_VISITS
where
DATE >= '01-01-15' and DATE <= '09-01-15'
group by
PAGE
请问我怎样才能使平均值起作用?
最佳答案
只需省略 , 0
。我更喜欢 case
,所以我会这样写:
select PAGE,
AVG(CASE WHEN VISIT_TYPE = 'AM' THEN AVERAGE_PAGE_LOAD_DUR END) AS AVG_AM,
AVG(CASE WHEN VISIT_TYPE = 'PM' THEN AVERAGE_PAGE_LOAD_DUR END) AS AVG_PM,
from PAGE_VISITS
where DATE >= '2015-01-01' and DATE <= '2015-09-01'
group by PAGE;
注意事项:
AVG()
忽略NULL
值,但它在计算中包含0
。- 作为平均值计算的列可能不应该称为
SUM()
。 - 使用 ISO 和 MySQL 标准日期格式:YYYY-MM-DD
最后,如果您对每页两行感到满意,那么这就更简单了:
select PAGE, AVG(AVERAGE_PAGE_LOAD_DUR) AS AVG_page_load
from PAGE_VISITS
where DATE >= '2015-01-01' and DATE <= '2015-09-01'
group by PAGE, VISIT_TYPE
关于MySQl - AVG ( AVG IF) & 分组依据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37052672/