mysql - 如何关联两个未通过键直接连接的mysql表

Question

我有以下两个 mysql 表。

表名:分析

id   execution_time
---  --------------
A1   1
A2   20
A3   35

表名:错误

bug_id creation_time
------ -------------
1000   1.1
1001   1.3
1002   20.2
1003   20.7
1004   20.9
1005   35.1

错误 1000、1001 是为分析 A1 创建的

错误 1002、1003、1004 是为分析 A2 创建的

错误 1005 是为分析 A3 创建的

因此，Bug creation_time 总是大于它的 Analysis 的 execution_time，而 bug_creation_time 总是小于后面分析的执行。

现在，1) 如果我有一个分析 ID，我如何找到相关的错误 (bug_id)。

2)如何找到给定错误数据(id，creation_time)的相关分析id

Answer 1

1) SQL FIDDLE DEMO

SELECT b.*, t.*
FROM Bugs b
CROSS JOIN (  SELECT a1.id, 
                     a1.`execution_time` as `start_time`, 
                     a2.`execution_time` as `end_time`
              FROM Analysis a1
              LEFT JOIN Analysis a2
                 ON a1.`execution_time` < a2.`execution_time`  
              WHERE a2.`execution_time` IS NULL
                 OR a2.`execution_time`  = (SELECT min( z.`execution_time`)
                                            FROM Analysis z
                                            WHERE z.`execution_time` > a1.`execution_time`)
            ) t
WHERE b.`creation_time` between `start_time` and `end_time`
   or (b.`creation_time` > `start_time` and `end_time` IS NULL)

输出:只需要按 id 过滤

2)

SELECT *
FROM Analysis a
WHERE a.id = (  SELECT MAX(id)
                FROM Analysis a
                WHERE a.execution_time < @bugCreationTime)