php - 在表中显示来自查询的行

Question

我有这段代码可以从我的产品表中获取所有数据。它像这样工作得很好:

if ($result->num_rows > 0) {
        // output data of each row
        while($row = $result->fetch_assoc()) {
            echo $row['id'];
            echo $row['country'];
            echo $row['price'];
            echo $row['games'];
            echo $row['plus'];
            echo $row['buylink'];
            echo "<br/>";
        }

但我希望这些结果显示在正文内的表格中。我尝试了一些东西，但没有用。

表格是这样的:

<table class="table table-hover table-striped table-condensed">
<thead>
  <tr>
    <th>ID</th>
    <th>Country</th>
    <th>Price</th>
    <th>Games</th>
    <th>Plus</th>
    <th>Buy Link</th>
  </tr>
</thead>
<tbody>
  <tr>
    <td><?php echo $row['id']; ?></td>
    <td><?php echo $row['country']; ?></td>
    <td><?php echo $row['price']; ?></td>
    <td><?php echo $row['games']; ?></td>
    <td><?php echo $row['plus']; ?></td>
    <td><?php echo $row['buylink']; ?></td>

  </tr>
</tbody>

Answer 1

<?php
if ($result->num_rows > 0) {
?>
<table class="table table-hover table-striped table-condensed">
  <thead>
    <tr>
      <th>ID</th>
      <th>Country</th>
      <th>Price</th>
      <th>Games</th>
      <th>Plus</th>
      <th>Buy Link</th>
    </tr>
  </thead>
  <tbody>
  <?php while($row = $result->fetch_assoc()){ ?>
    <tr>
      <td><?php echo $row['id']; ?></td>
      <td><?php echo $row['country']; ?></td>
      <td><?php echo $row['price']; ?></td>
      <td><?php echo $row['games']; ?></td>
      <td><?php echo $row['plus']; ?></td>
      <td><?php echo $row['buylink']; ?></td>
    </tr>
  <?php }?>
  </tbody>
</table>
<?php
}else {
 // if there is no result... Code something here.
}
?>