我有一个如下所示的查询:
select uid,leadcount,salescount,leadcount/salescount as diff from
(
SELECT x.uid, COUNT(*) leadcount, COUNT(DISTINCT x.fid)
FROM total_leads AS x
WHERE x.uid BETWEEN 1 AND 5
GROUP BY x.uid
) t1 left join
(
SELECT ud.UserId, COUNT(*) salescount, COUNT(DISTINCT ud.SalesID)
FROM total_sales AS ud
WHERE ud.UserId BETWEEN 1 AND 5
GROUP BY ud.UserID
) t2 on t1.uid=t2.UserId
结果是:
我试图只显示 diff
大于 2.5
的结果(所以在这种情况下只显示 uid
5 应该在输出中可见)。
我尝试使用 WHERE diff >= 2.5
但我得到了“你的 SQL 语法有错误”。
最佳答案
只需在 WHERE
子句中重复原始表达式而不是使用别名:
SELECT uid leadcount, salescount, leadcount/salescount AS diff
FROM
(
...
) t
WHERE leadcount/salescount >= 2.5;
在 WHERE
子句中引用 diff
的问题在于它尚不可用。另外,假设您不打算聚合,请参阅戈登的另一个选项的答案。但是,使用 HAVING
只是 MySQL 或 MariaDB 上的一个选项。
关于mysql - MariaDB 仅选择大于的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54739655/