mysql - 在sql结果中排序

Question

我有自定义查询从数据库中获取数据。我在订购时遇到问题。

这是我用来获取数据的方法。

SELECT a.*, b.* FROM wp_terms AS a INNER JOIN wp_term_taxonomy AS b ON a.term_id = b.term_id
            WHERE
                b.taxonomy = "ticker" AND(
                    a.name LIKE "aa%" OR b.description LIKE "aa%"
                )
            ORDER BY 
                CASE 
                    WHEN(
                            a.name LIKE "aa%" AND b.description LIKE "aa%"
                        ) THEN 1 
                    WHEN(
                            a.name LIKE "aa%" AND b.description NOT LIKE "aa%"
                        ) THEN 2 
                    ELSE 3
                    END,a.name ASC
            LIMIT 0, 10

结果是这样显示的。

显示我需要一个结果来显示

AA

首先是其他结果。

它正在处理单个字符

SELECT a.*, b.* FROM wp_terms AS a INNER JOIN wp_term_taxonomy AS b ON a.term_id = b.term_id
            WHERE
                b.taxonomy = "ticker" AND(
                    a.name LIKE "v%" OR b.description LIKE "v%"
                )
            ORDER BY 
                CASE 
                    WHEN(
                            a.name LIKE "v%" AND b.description LIKE "v%"
                        ) THEN 1 
                    WHEN(
                            a.name LIKE "v%" AND b.description NOT LIKE "v%"
                        ) THEN 2 
                    ELSE 3
                    END,a.name ASC
            LIMIT 0, 10

Answer 1

字母排序的最佳解决方案是先按长度排序，然后按值排序 -

SELECT a.*,
  b.*
FROM wp_terms               AS a
INNER JOIN wp_term_taxonomy AS b
ON a.term_id     = b.term_id
WHERE b.taxonomy = "ticker"
AND( a.name LIKE "aa%"
OR b.description LIKE "aa%" )
ORDER BY
  CASE
    WHEN( a.name LIKE "aa%"
    AND b.description LIKE "aa%" )
    THEN 1
    WHEN( a.name LIKE "aa%"
    AND b.description NOT LIKE "aa%" )
    THEN 2
    ELSE 3
  END,
  LENGTH(a.name),
  a.name ASC LIMIT 0,
  10