php - 我哪里错了？查询

Question

$foot = mysql_query("SELECT count(*) 
                       FROM tblQA 
                      WHERE intResponseID = '' 
                        AND cCategory = 'Football' as qcount, 
                    (SELECT max(dPostDateTime) 
                       FROM tblQA 
                      WHERE intResponseID = '' 
                        AND cCategory = 'Football') as lastq");


$football = mysql_fetch_array($foot);

echo "<td class='forum'>" . $footbll['qcount'] . "</td>";
echo "<td class='forum'>" . $footbll['lastq'] . "</td>";

这不会在我的表格中显示任何内容。我没有发布完整的 HTML 代码，我的表结构很好。

Answer 1

使用:

$foot = mysql_query("SELECT COUNT(*) AS qcount,
                            MAX(dPostDateTime) AS lastq
                      FROM tblQA 
                     WHERE intResponseID = '' 
                       AND cCategory = 'Football' ");

$football = mysql_fetch_array($foot);

echo "<td class='forum'>" . $football['qcount'] . "</td>";
echo "<td class='forum'>" . $football['lastq'] . "</td>";

我重写了您的查询，这一切都可以在一条语句中完成。