php - while 循环总是打印最后插入的行结果

标签 php mysql if-statement while-loop

问题是 while 循环总是显示最后插入的行结果。我试过下面的代码来关注/取消关注按钮选项。比如我是一个用户id=1。我已经关注了用户id=4。现在,我想关注用户id=5。当我点击关注按钮(id=5)时,它会正确地变成取消关注。但是,我已经关注了用户id=4。那变成跟随。这是我的问题。

然后我尝试了 echo $following;。它打印 5555。这意味着最后插入的数据。但我想要 45。我确信我在 while 循环中犯了一个错误。但是我不知道我应该改变什么?

        <?php
                try
                {
                    $stmt = $conn->prepare("SELECT * FROM users ORDER BY Autoid");
                    $stmt->errorInfo();
                    $stmt->execute();

                    $sth = $conn->prepare("SELECT * FROM followers ORDER BY Autoid");
                    $sth->errorInfo();
                    $sth->execute();
                    while($follow_row = $sth->fetch(PDO::FETCH_ASSOC))
                   {
                        $following = $follow_row['Following'];
                        $follower = $follow_row['Follower'];
                   }

                    while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
                       {
                        echo "<tr>";
                        echo "<td>". $row['Autoid'] ."</td>";
                        echo "<td>". $row['Name'] ."</td>";

                        // echo $row['Following'];
                        if($_SESSION['sesuname'] == $row['Username'])
                         {
                            echo "<td class='itsyou' >Its You ". $_SESSION['sesuname'] ."</td>";
                         }
                        else
                         {  
                            if(($follower == $_SESSION['sesid']) AND ($following != $row['Autoid']))
                            {
                               //echo "<td>true</td>";
                             echo $following;
                             echo "<td>";
                             echo "<form id='jsform' method='post' action='subscribe.php'>";
                             echo "<input type='hidden' name='id' value=" . $row['Autoid'] . " />";
                             echo "<button class='follow' >Follow</button>";
                             echo "</form>";
                             echo "</td>";                             
                            }
                            else
                            {
                                //echo "<td>false</td>";
                             echo "<td>";
                             echo "<form id='ufform' method='post' action='unsubscribe.php'>";
                             echo "<input type='hidden' name='uid' value=" . $row['Autoid'] . " />";
                             echo "<button class='follow' >UnFollow</button>";
                             echo "</form>";
                             echo "</td>";
                            }
                         }
                        echo "</tr>";
                     }
                } catch (PDOException $e) {
                       'Database Error : ' .$e->getMessage();
                }
            ?>

最佳答案

这段代码:

    while($follow_row = $sth->fetch(PDO::FETCH_ASSOC))
   {
        $following = $follow_row['Following'];
        $follower = $follow_row['Follower'];
   }

每次获取一行时,只需覆盖 $following$follower,留下变量中获取的 LAST 行。也许你想要更像的东西

    $following[] = $follow_row['Following'];
    $follower[] = $follow_row['Follower'];
             ^^--- append new row value to an array.

关于php - while 循环总是打印最后插入的行结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22341747/

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