我需要获取每个用户的唯一计数以及国家/地区计数和总费率
我想出了这个数据库的基本设计,其中 uid
是用户 id
DROP TABLE IF EXISTS `stats`;
CREATE TABLE IF NOT EXISTS `stats` (
`id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`uid` int(5) UNSIGNED NOT NULL,
`country` int(3) UNSIGNED NOT NULL,
`ip` int(10) UNSIGNED NOT NULL,
`date` int(10) UNSIGNED NOT NULL,
`timestamp` int(10) UNSIGNED NOT NULL,
`rate` int(10) UNSIGNED NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci;
INSERT INTO `stats`
(`id`, `uid`, `country`, `ip`, `date`, `timestamp`, `rate`) VALUES
(1, 1, 10, 1111111111, 2222222222, 3333333333, 100),
(2, 1, 10, 1111111112, 2222222222, 3333333333, 100),
(3, 2, 10, 1111111111, 2222222222, 3333333333, 100),
(4, 1, 10, 1111111114, 2222222223, 3333333333, 100),
(5, 1, 11, 1111111112, 2222222223, 3333333333, 100),
(6, 1, 10, 1111111111, 2222222223, 3333333333, 100);
这是我用来获取每日计数的查询
$query="
SELECT `uid`,
COUNT(DISTINCT `ip`)AS `count`,
`country`,
SUM(`rate`) AS `sum`,
`date`
FROM `stats`
GROUP BY `uid`, `date`
";
$result=mysqli_query($connection, $query) or trigger_error(mysqli_error($connection), E_USER_ERROR);
while($row = mysqli_fetch_assoc($result)){
echo 'userid:'.$row['uid'].' count:'.$row['count'].' country:'.$row['country'].' sum:'.$row['sum'].' date:'.$row['date'].'<br>';
};
我得到这个结果
userid:1 count:2 country:10 sum:200 date:2222222222
userid:1 count:3 country:10 sum:300 date:2222222223
userid:2 count:1 country:10 sum:100 date:2222222222
预期结果
userid:1 count:2 country:10=>2 sum:200 date:2222222222
userid:1 count:3 country:10=>2, 11=>1 sum:300 date:2222222223
userid:2 count:1 country:10=>1 sum:100 date:2222222222
我想我需要像 SELECT DISTINCT country FROM stats
这样的东西来在主查询中获取国家/地区计数。
请查看并提出任何可能的方法。
谢谢
最佳答案
您可以使用子查询来实现这一点:
SELECT
t.uid,
SUM(t.count) AS count,
GROUP_CONCAT(CONCAT(t.country, ' => ', t.views) SEPARATOR ', ') AS country,
SUM(t.sum) as sum,
t.date
FROM (
SELECT
s.uid,
COUNT(DISTINCT s.ip) AS count,
s.country,
COUNT(s.country) as views,
SUM(s.rate)AS sum,
s.date
FROM stats s
GROUP BY uid, date, country
) AS t
GROUP BY
t.uid,
t.date
也可在 sqlfiddle 获得.
关于php - Mysql从统计数据库中获取多个计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39138803/