MySQL - JOIN - 在另一个表中找到最大值并显示第一个表中的客户名称

Question

select discount.RATE, customer.NAME 
from APP.DISCOUNT_CODE as discount 
LEFT JOIN APP.CUSTOMER as customer 
ON discount.DISCOUNT_CODE = customer.DISCOUNT_CODE;

当我使用这个查询时，我得到了所有的折扣率和客户名称，但我只想显示一个有最大折扣的客户。RATE..

我试过这个查询..

select max(discount.RATE), customer.NAME 
from APP.DISCOUNT_CODE as discount 
LEFT JOIN APP.CUSTOMER as customer 
ON discount.DISCOUNT_CODE = customer.DISCOUNT_CODE;

但是我得到一个错误..如何解决这个问题..

这是第一个查询的表..

错误是 get 正在使用 max(discount.RATE) 运行第二个查询，

[Exception, Error code 30,000, SQLState 42Y35] Column reference 'CUSTOMER.NAME' is invalid. When the SELECT list contains at least one aggregate then all entries must be valid aggregate expressions.  

Answer 1

SELECT
    discount.RATE, customer.NAME
    FROM
        APP.DISCOUNT_CODE as discount
        JOIN APP.CUSTOMER as customer ON discount.DISCOUNT_CODE = customer.DISCOUNT_CODE
    ORDER BY
        discount.RATE DESC
    LIMIT 1