MySQL NOT IN 运算符

Question

我有以下数据，其中包含 2 个不同的 TBL_ID - 337448 和 8612

"TBL_ID","PARAM_KEY","PARAM_VALUE"
 337448,"comment","CHANGE DUE"
 337448,"transient_lastDdlTime","1505760292"
 8612,"COLUMN_STATS_ACCURATE","true"
 8612,"numFiles","1"
 8612,"numRows","5294"
 8612,"rawDataSize","-1"
 8612,"totalSize","113217"
 8612,"transient_lastDdlTime","1452191300"

我需要查询所有不包含“numRows”的TBL_ID 我尝试过的:

SELECT * FROM TABLE_PARAMS 
WHERE PARAM_KEY NOT IN ('numRows')

结果:

"TBL_ID","PARAM_KEY","PARAM_VALUE"
 337448,"comment","CHANGE DUE"
 337448,"transient_lastDdlTime","1505760292"
 8612,"COLUMN_STATS_ACCURATE","true"
 8612,"numFiles","1"
 8612,"rawDataSize","-1"
 8612,"totalSize","113217"
 8612,"transient_lastDdlTime","1452191300"

它确实删除了带有 numRows 的列，但我需要删除整个 TBL_ID (8612)

Answer 1

你的问题有点模棱两可。 IN 运算符用于从结果集中查找数据。例如 2 IN {2, 3, 4}。

SELECT TBL_ID FROM  TABLE_PARAMS
WHERE PRAMAR_KEY='numRows'

如果您试图不显示任何与 numRows 关联的 ID，那么您必须首先获取要过滤的 ID，并且用户不等于。 例如，如果您尝试从您的集合中删除 8612 因为它是 Param_Key ='numRows' 的 ID 并且如果您尝试在 OPERATOR 中使用，那么

SELECT * FROM TABLE_PARAMS
WHERE TBL_ID NOT IN (SELECT TBL_ID FROM TABLE_PARAMS WHERE PARAM_KEY='numRows')