需要使 $courseInfo 和 $row 全局化，以便它们可用于打印标题 DIV 中的行详细信息。
不知道如何做到这一点。任何帮助都会很棒。
<?php
// Get Course ID From Link
$ID = mysql_real_escape_string($_REQUEST['ID']);
// Check the Course ID exists
$courseCheck = mysql_query("SELECT * FROM Courses WHERE CourseID = '".$ID."'");
if (mysql_num_rows($courseCheck) == 1) {
$checkMember = mysql_query("SELECT * FROM CourseMembers WHERE CourseID = '".$ID."' AND UserID = '".$_SESSION['UserID']."'");
if (mysql_num_rows($checkMember) == 1) {
?>
<html>
<head>
<!-- Style Sheets -->
<link rel="stylesheet" href="style/reset.css" type="text/css" media=screen />
<link rel="stylesheet" href="style/style.css" type="text/css" media=screen />
</head>
<body>
<?php
if ($_SESSION['LoggedIn'] == 1){
$courseInfo = mysql_query("SELECT * FROM Courses WHERE CourseID = '".$ID."'");
$row = mysql_fetch_assoc($courseInfo);
?>
<div id="container">
<div id="side">
<?php include("lib/sidebar.php"); ?>
</div>
<div id="main">
<div id="mainbox">
<div id="header"><b><?php echo $row['CourseName']; ?></b></div>
<p>Hello world, this is a test.</p>
</div>
</div>
</div>
<div class="clear"></div>
<?php
}
else {
echo "Not logged in.";
}
}
else {
echo "You are not a member of this Course";
}
}
else {
echo "No Course Found";
}
?>
</body>
最佳答案
我认为它们已经是全局性的。 "PHP does not have a block-level scope."
关于php - 在 PHP 中使变量成为全局变量？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4770106/