我有以下查询
SELECT
interview_content.title `title`,
gallery_images.img_path img
FROM
`interview`,
`interview_content`,
`gallery`,
`gallery_images`
WHERE
`gallery_images`.`id_parrent` = `gallery`.`id`
AND
`gallery`.`id` = `interview`.`gallery_id`
AND
`gallery_images`.`default` = '1'
AND
`interview`.`id` = `interview_content`.`id_parrent`
AND
interview_content.id_lang = '2'
ORDER BY
interview.date DESC
我需要在 gallery
、gallery_images
表上使用 LEFT JOIN(即使没有 gallery 也能获得 interview.title
或默认图像)
非常感谢
更新
问题出在第二个 LEFT JOIN 中。我无法让它们一起正常工作。当我尝试
SELECT
interview_content.title `title`,
gi.img_path img
FROM
`interview`,
`interview_content`
LEFT JOIN `gallery` as g ON g.`id` = `interview`.`gallery_id`
LEFT JOIN `gallery_images` as gi ON gi.id_parrent = g.`id`
WHERE
`interview`.`id` = `interview_content`.`id_parrent`
AND
interview_content.id_lang = '2'
ORDER BY
interview.date DESC
it returns //Unknown column 'interview.gallery_id' in 'on clause'
最佳答案
你知道你需要做什么。 Google 是你的 friend 吗?
关于php - 如何在此查询中使用 LEFT JOIN,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5020074/