我在这里遇到错误，非常感谢您的帮助。
我的代码在下面，这是我得到的错误:
PHP 警告:mysqli_fetch_array() 期望参数 1 为 mysqli_result，在第 14 行的/home/SANDBOX/PHP/.php 中给定为 null
<?php
$con=mysqli_connect("localhost","USER","PASSWORD","DATABASE");
// Check connection
if (mysqli_connect_errno()){
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if($_POST[process]=="btn_add"){
$result = mysqli_query($con,"INSERT INTO users (user, password, type) VALUES ('".$_POST['user']."','".$_POST['password']."','".$_POST['type']."')" );
}else if($_POST[process]=="btn_update"){
$result = mysqli_query($con,"UPDATE users SET user='".$_POST['user']."', password='".$_POST['password']."', type='".$_POST['type']."' WHERE id='".$_POST['id']."' ;");
}else if($_POST[process]=="btn_delete"){
$result = mysqli_query($con,"DELETE FROM users WHERE id='".$_POST['id']."';");
}while($result = mysqli_fetch_array($row)){
echo $row['type'] ;
}
mysqli_close($con);
?>
最佳答案
mysqli_fetch_array($row) 到 mysqli_fetch_array($result)
关于缺少参数的查询中的 PHP 错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20441490/