mysql - 尝试删除数据时查询出错

Question

我试图从 Workbench 中的表中删除一些数据，但是当我按下删除按钮时，我得到了这个错误；

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Name='Stephenie Meyer' and Year_of_birth='1985'' at line 1.

这是代码:

$author=$_POST['AuthorID'];
$name=$_POST['Name'];
$year=$_POST['Year_of_birth'];

$author=htmlspecialchars($author);
$name=htmlspecialchars($name);
$year=htmlspecialchars($year);

if($db_found)
{
      $SQL="SELECT*from books WHERE AuthorID='$author' Name='$name' and Year_of_birth='$year'";
      $result=mysql_query($SQL) or die(mysql_error());

        while($row=mysql_fetch_assoc($result))
         {
             echo "<tr><td>".$row["AuthorID"]."</td><td>".$row["Name"]."</td><td>".$row["Year_of_birth"]."</td></tr>" ;

         }
         echo "</table><br>";
         $DQL="DELETE from books WHERE AuthorID='$author' , Name='$name' and Year_of_birth='$year'";
         if ($db_handle->query($DQL) === TRUE) 
           {
            echo "Record(s) deleted successfully";
           }
            else 
            {
            echo "Error deleting record: " . $db_handle->error;
            }
       }
       else
       {
          echo"Record not found";
       }

你能帮忙吗？

Answer 1

你有几个语法错误。

1. 您遗漏了一个AND
2. 添加一些空格

改变:

 $SQL="SELECT*from books WHERE AuthorID='$author' Name='$name' and Year_of_birth='$year'";

到

 $SQL="SELECT * FROM books WHERE AuthorID='$author' AND Name='$name' AND Year_of_birth='$year'";

另外，请研究用 PHP 而不是 mysql_query 执行 MySQL 查询的更现代的方法。它已被弃用。查看文档:http://php.net/manual/en/function.mysql-query.php