mysql - Order By 不使用 Top MS SQL 查询

标签 mysql sql-server sorting datatable

我正在创建一个查询,它应该适合我在 MsSQL 中处理的数据表。这是我第一次使用 MsSQL,所以我试图从我的 MySQL 中找出等效的 MsSQL 查询。

我做了一个自定义查询,它将处理 MySQL 中的 LIMIT 函数到 MsSQL(希望如此)。我在数据表中使用了以下查询:

    SELECT * FROM (
        SELECT top 20 CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) AS week_name, 
        AVG(DATEDIFF(day, CONVERT(date, [UnloadDate]), CONVERT(date, [DeliveryDate]))) as Average_Delivery_Days
        FROM [CARGODB].[dbo].[Cargo_Transactions] 
        WHERE [DeliveryDate] IS NOT NULL AND [DeliveryDate] != 0 
        AND [UnloadDate] IS NOT NULL AND [UnloadDate] != 0 AND [DeliveryDate] > [UnloadDate] AND [Deleted] = 0 and [StageID] = 'D' 
        AND [RouteID] IS NOT NULL AND [RouteID] != '' AND CONVERT(date, [DeliveryDate]) BETWEEN '2016-01-01' AND GETDATE() 
        AND CONVERT(date, [DeliveryDate]) >= DATEADD(week, -24, getdate()) 
        GROUP BY DATEPART(YEAR,[DeliveryDate]), DATEPART(WEEK,[DeliveryDate]) 
        ORDER BY CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) ASC
    ) as foo
    except
    SELECT * FROM (
        SELECT top 10 CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) AS week_name, 
        AVG(DATEDIFF(day, CONVERT(date, [UnloadDate]), CONVERT(date, [DeliveryDate]))) as Average_Delivery_Days
        FROM [CARGODB].[dbo].[Cargo_Transactions] 
        WHERE [DeliveryDate] IS NOT NULL AND [DeliveryDate] != 0 
        AND [UnloadDate] IS NOT NULL AND [UnloadDate] != 0 AND [DeliveryDate] > [UnloadDate] AND [Deleted] = 0 and [StageID] = 'D' 
        AND [RouteID] IS NOT NULL AND [RouteID] != '' AND CONVERT(date, [DeliveryDate]) BETWEEN '2016-01-01' AND GETDATE() 
        AND CONVERT(date, [DeliveryDate]) >= DATEADD(week, -24, getdate()) 
        GROUP BY DATEPART(YEAR,[DeliveryDate]), DATEPART(WEEK,[DeliveryDate]) 
        ORDER BY CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) ASC
    ) as bar

结果是:

week_name     | Average_Delivery_Days
==================================
2017 Week 36  | 15
2017 Week 39  | 11
2017 Week 41  | 13
2017 Week 42  | 10
2017 Week 38  | 12
2017 Week 40  | 12
2017 Week 35  | 14
2017 Week 43  | 6
2017 Week 37  | 12
2017 Week 44  | 9

但我希望它按周数升序排序,因此它应该显示 36、37、38、39 等等。

我的查询中可能遗漏了什么?

感谢您的帮助。谢谢!

最佳答案

您的 ORDER BY 子句只影响 TOP 选择;它不对结果集进行排序。在查询末尾添加一个 ORDER BY 应该可以解决问题。

但是,我确实看到了另一个问题,即您要对其中包含数字的 VARCHAR 列进行排序。 VARCHAR 按字母顺序排序,因此第 2 周将出现在第 19 周之后。所以我会这样做:

SELECT 
/* Explicitly select these columns */
week_name
, Average_Delivery_Days


FROM (
    SELECT top 20
    /* Add separate columns for numerical year and week */
     iyear = YEAR(DeliveryDate)
    , iweek = DATEPART(WEEK,DeliveryDate)
    , CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) AS week_name, 
    AVG(DATEDIFF(day, CONVERT(date, [UnloadDate]), CONVERT(date, [DeliveryDate]))) as Average_Delivery_Days
    FROM [CARGODB].[dbo].[Cargo_Transactions] 
    WHERE [DeliveryDate] IS NOT NULL AND [DeliveryDate] != 0 
    AND [UnloadDate] IS NOT NULL AND [UnloadDate] != 0 AND [DeliveryDate] > [UnloadDate] AND [Deleted] = 0 and [StageID] = 'D' 
    AND [RouteID] IS NOT NULL AND [RouteID] != '' AND CONVERT(date, [DeliveryDate]) BETWEEN '2016-01-01' AND GETDATE() 
    AND CONVERT(date, [DeliveryDate]) >= DATEADD(week, -24, getdate()) 
    GROUP BY DATEPART(YEAR,[DeliveryDate]), DATEPART(WEEK,[DeliveryDate]) 
    ORDER BY CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) ASC
) as foo
except
SELECT * FROM (
    SELECT top 10 CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) AS week_name, 
    AVG(DATEDIFF(day, CONVERT(date, [UnloadDate]), CONVERT(date, [DeliveryDate]))) as Average_Delivery_Days
    FROM [CARGODB].[dbo].[Cargo_Transactions] 
    WHERE [DeliveryDate] IS NOT NULL AND [DeliveryDate] != 0 
    AND [UnloadDate] IS NOT NULL AND [UnloadDate] != 0 AND [DeliveryDate] > [UnloadDate] AND [Deleted] = 0 and [StageID] = 'D' 
    AND [RouteID] IS NOT NULL AND [RouteID] != '' AND CONVERT(date, [DeliveryDate]) BETWEEN '2016-01-01' AND GETDATE() 
    AND CONVERT(date, [DeliveryDate]) >= DATEADD(week, -24, getdate()) 
    GROUP BY DATEPART(YEAR,[DeliveryDate]), DATEPART(WEEK,[DeliveryDate]) 
    ORDER BY CAST(DATEPART(YEAR,[DeliveryDate]) as varchar) + ' Week ' + CAST(DATEPART(WEEK,[DeliveryDate]) AS varchar) ASC
) as bar
 /* sort by the numeric columns */
 ORDER BY foo.iyear, foo.iweek

关于mysql - Order By 不使用 Top MS SQL 查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47661018/

相关文章:

javascript - 按频率对 Javascript 数组进行排序,然后过滤重复

即使对列建立索引后,MySQL 日志仍很慢

SQL Server 相当于 GROUP_CONCAT()

sql - T-SQL Azure 流分析四舍五入到分钟

algorithm - 使用 perl 按依赖项排序数组

sorting - awk 根据特定列值完全删除重复行

mysql - 同步地理上不同的 mysql 服务器的最佳方法是什么?

MYSQL 过程没有被调用

MySQL 在主键搜索时使用 ALL 类型

sql-server - 从预定义列表中选择随机数据