在检查要求用户打开互联网服务后,我尝试点击一个按钮,我的应用程序崩溃并显示错误消息
java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.
在这一行它崩溃了,我试过这样做但没有完全解决
if(alert.getContext() != null){
alert.show();
}
这是完整的代码
else if (id == R.id.xyz) {
//startActivity(borrowIntent);
AlertDialog.Builder alert = new AlertDialog.Builder(MainActivity.this);
alert.setTitle("xyz");
input.setFilters(new InputFilter[] {
// Maximum 2 characters.
new InputFilter.LengthFilter(6),
// Digits only.
DigitsKeyListener.getInstance(),
});
// Digits only & use numeric soft-keyboard.
input.setKeyListener(DigitsKeyListener.getInstance());
input.setHint("xyz");
alert.setView(input);
alert.setPositiveButton("Borrow", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
if(input.getText().length() == 0)
{
input.setError("xyz is required !");
}
else
{
if(isNetworkAvailable())
{
xyz( input.getText().toString());
}else{
//setContentView(R.layout.main);
AlertDialog.Builder builder = new AlertDialog.Builder(
MainActivity.this);
builder.setCancelable(false);
builder.setTitle("xyz");
builder.setMessage("Please enable wifi services");
builder.setInverseBackgroundForced(true);
builder.setPositiveButton("Ok",
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog,
int which) {
startActivityForResult(new Intent(android.provider.Settings.ACTION_SETTINGS), 0);
dialog.dismiss();
}
});
AlertDialog alerts = builder.create();
alerts.show();
}//end of block
}
}
});
alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// Canceled.
}
});
if(alert.getContext() != null){
alert.show(); //crashes at this line
}
}
请问我错过了什么?
最佳答案
问题出在这一行:
alert.setView(输入);
您添加的 input
View
已经有 parent
。
创建新的 input
实例。
关于java - dialog - 指定的子项已经有一个父项。您必须先对 child 的 parent 调用 removeView(),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37456215/