mysql - 如何选择所有项目完成的所有订单？

Question

我有以下表格:

CREATE TABLE `orders` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `user_id` int(10) unsigned NOT NULL,
  `billing_profile_id` int(10) unsigned NOT NULL,
  `name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `currency` varchar(3) COLLATE utf8_unicode_ci NOT NULL,
  `valid_until` timestamp NULL DEFAULT NULL
)

和:

CREATE TABLE `items` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `order_id` int(10) unsigned NOT NULL,
  `status` enum('pending','processing','completed','on-hold','cancelled'),
  `code` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `quantity` int(10) unsigned NOT NULL DEFAULT '1',
  `term` int(10) unsigned NOT NULL,
  `name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `discounts` int(10) unsigned NOT NULL,
  `total` int(10) unsigned NOT NULL
)

如何仅选择其所有状态为已完成的订单？

我试过这个:

SELECT o.* FROM 
FROM orders o INNER JOIN items i on o.id=i.order_id
GROUP BY o.id, i.status
HAVING i.status = 'completed'

但这只会返回具有一些 项目已完成 的订单，而不是所有。

编辑:没有items 的order 也是有效结果。

Answer 1

试试这个:

SELECT *
FROM   orders
WHERE  EXISTS (SELECT *
               FROM   items
               WHERE  orders.id = items.order_id
                 AND  items.status = 'completed')
  AND  NOT EXISTS (SELECT *
                   FROM   items
                   WHERE  orders.id = items.order_id
                     AND  items.status <> 'completed')