我正在尝试创建一个登录 android 系统,当我尝试登录时,第 74 行出现错误 "undefined function consigueResultado"
,但我声明了该函数。有谁知道可能出了什么问题?
我正在使用 000webhost 是否与此错误有关?谢谢:)
<?php
class DB_Functions {
private $conn;
// constructor
function __construct() {
require_once 'DB_Connect.php';
// connecting to database
$db = new Db_Connect();
$this->conn = $db->connect();
}
// destructor
function __destruct() {
}
public function consigueResultado( $stmt ) {
$RESULT = array();
$stmt->store_result();
for ( $i = 0; $i < $stmt->num_rows; $i++ ) {
$Metadata = $stmt->result_metadata();
$PARAMS = array();
while ( $Field = $Metadata->fetch_field() ) {
$PARAMS[] = &$RESULT[ $i ][ $Field->name ];
}
call_user_func_array( array( $stmt, 'bind_result' ), $PARAMS );
$stmt->fetch();
}
return $RESULT;
}
/**
* Storing new user
* returns user details
*/
public function storeUser($name, $email, $password) {
$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$encrypted_password = $hash["encrypted"]; // encrypted password
$salt = $hash["salt"]; // salt
$stmt = $this->conn->prepare("INSERT INTO users(unique_id, name, email, encrypted_password, salt, created_at) VALUES(?, ?, ?, ?, ?, NOW())");
$stmt->bindParam("sssss", $uuid, $name, $email, $encrypted_password, $salt);
$result = $stmt->execute();
$stmt->close();
// check for successful store
if ($result) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE email = :email");
$stmt->bindParam(':email', $email);
$stmt->execute();
$user = consigueResultado( $stmt );
$stmt->close();
return $user;
} else {
return false;
}
}
/**
* Get user by email and password
*/
public function getUserByEmailAndPassword($email, $password) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE email =:email");
$stmt->bindParam(':email', $email);
if ($stmt->execute()) {
$user = consigueResultado( $stmt );
$stmt->close();
return $user;
} else {
return NULL;
}
}
/**
* Check user is existed or not
*/
public function isUserExisted($email) {
$stmt = $this->conn->prepare("SELECT email from users WHERE email = :email");
$stmt->bindParam(':email', $email);
$stmt->execute();
$stmt->store_result();
if ($stmt->num_rows > 0) {
// user existed
$stmt->close();
return true;
} else {
// user not existed
$stmt->close();
return false;
}
}
/**
* Encrypting password
* @param password
* returns salt and encrypted password
*/
public function hashSSHA($password) {
$salt = sha1(rand());
$salt = substr($salt, 0, 10);
$encrypted = base64_encode(sha1($password . $salt, true) . $salt);
$hash = array("salt" => $salt, "encrypted" => $encrypted);
return $hash;
}
/**
* Decrypting password
* @param salt, password
* returns hash string
*/
public function checkhashSSHA($salt, $password) {
$hash = base64_encode(sha1($password . $salt, true) . $salt);
return $hash;
}
}
?>
最佳答案
在类中我们必须使用 $this 关键字来调用当前类的方法,例如你的方法调用应该是这样的
$this->consigueResultado( $stmt );
关于出现未声明的 Php 函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33185389/