这是我获取所有权重的查询。:
$sumQuery = $conn->query("SELECT weightage FROM r_job_skill WHERE id_job = ".$jobID." AND gdskill = 1");
我得到这样的结果:
weightage
10
20
50
我想计算所有这些结果的总和,我该怎么做......?
最佳答案
或简称:
SELECT SUM(weightage)
FROM r_job_skill
WHERE id_job = ".$jobID."
AND gdskill = 1;
关于php - 如何在mysql中对所有结果求和,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41659992/