我一直在使用 PDO 构建注册表单。我是 PDO 的新手,所以我不完全理解为什么会出现该错误。我检查了我的代码,它似乎没有任何语法错误。我不知道它说访问冲突是什么意思。
我一直收到这个错误:
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]
这是我的连接文件
<?php
//Our MySQL user account.
define('MYSQL_USER', 'root');
//Our MySQL password.
define('MYSQL_PASSWORD', '');
//The server that MySQL is located on.
define('MYSQL_HOST', 'localhost');
//The name of our database.
define('MYSQL_DATABASE', 'private_beta_squire_app');
/**
* PDO options / configuration details.
* I'm going to set the error mode to "Exceptions".
* I'm also going to turn off emulated prepared statements.
*/
$pdoOptions = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_EMULATE_PREPARES => false
);
/**
* Connect to MySQL and instantiate the PDO object.
*/
$pdo = new PDO(
"mysql:host=" . MYSQL_HOST . ";dbname=" . MYSQL_DATABASE, //DSN
MYSQL_USER, //Username
MYSQL_PASSWORD, //Password
$pdoOptions //Options
);
?>
这是我的表单代码
<?php
require 'password.php';
if ( isset ( $_POST ['submitButton'] ) ) {
//if ( empty ( $_POST ['mail'] ) ) {
//echo "Type your mail";
//}
//if ( empty ( $_POST ['password'] ) ) {
//echo "Type your password";
//}
//if ( empty ( $_POST ['name'] ) ) {
//echo "Type your name";
//}
//else {
//Retrieve the field values from our registration form.
$username = !empty ( $_POST ['mail'] ) ? trim ( $_POST ['mail'] ) : null;
$pass = !empty ( $_POST ['password'] ) ? trim ( $_POST ['password'] ) : null;
$name = !empty ( $_POST ['name'] ) ? trim ( $_POST ['name'] ) : null;
$status = 'off';
//TO ADD: Error checking (username characters, password length, etc).
//Basically, you will need to add your own error checking BEFORE
//the prepared statement is built and executed.
//Now, we need to check if the supplied username already exists.
//Construct the SQL statement and prepare it.
$sql = "SELECT COUNT( email ) AS num FROM users WHERE email = :username";
$stmt = $pdo->prepare ( $sql );
//Bind the provided username to our prepared statement.
$stmt->bindValue ( ':username', $username );
//Execute.
$stmt->execute();
//Fetch the row.
$row = $stmt->fetch ( PDO::FETCH_ASSOC) ;
//If the provided username already exists - display error.
//TO ADD - Your own method of handling this error. For example purposes,
//I'm just going to kill the script completely, as error handling is outside
//the scope of this tutorial.
if ( $row ['num'] > 0 ) {
die ( 'That email is already registered!' );
}
//Hash the password as we do NOT want to store our passwords in plain text.
$passwordHash = password_hash ( $pass, PASSWORD_BCRYPT, array ( "cost" => 12 ) );
//Prepare our INSERT statement.
//Remember: We are inserting a new row into our users table.
$sql = "INSERT INTO users (email, name, status, pass) VALUES (:username, :name, :status, :password;)";
$stmt = $pdo->prepare($sql);
//Bind our variables.
$stmt->bindValue (':username', $username);
$stmt->bindValue (':name', $name);
$stmt->bindValue (':name', $status);
$stmt->bindValue (':password', $passwordHash);
//Execute the statement and insert the new account.
$result = $stmt->execute();
//If the signup process is successful.
if ( $result ) {
//What you do here is up to you!
header('location: index.php');
}
//}
}
?>
最佳答案
你有两个问题。
$sql = "INSERT INTO users (email, name, status, pass) VALUES (:username, :name, :status, :password;)";
- 在 `password` 占位符之后的 `;` 关闭了 `insert` 语句,这使得查询无效。
$stmt->bindValue (':name', $name);
$stmt->bindValue (':name', $status);
- 虽然您的查询使用了正确的名称,但您在这里使用了相同的占位符名称两次。如果您使用未命名的占位符,这不会导致问题。
所以你应该:
$sql = "INSERT INTO users (email, name, status, pass) VALUES (:username, :name, :status, :password)";
$stmt = $pdo->prepare($sql);
//Bind our variables.
$stmt->bindValue (':username', $username);
$stmt->bindValue (':name', $name);
$stmt->bindValue (':status', $status);
$stmt->bindValue (':password', $passwordHash);
//Execute the statement and insert the new account.
$result = $stmt->execute();
备选方案:
$sql = "INSERT INTO users (email, name, status, pass) VALUES (?, ?, ?, ?)";
$stmt = $pdo->prepare($sql);
//Bind and execute the statement and insert the new account.
$result = $stmt->execute(array($username, $name, $status, $passwordHash));
关于php - 这是什么意思?我该如何解决?未捕获的异常 'PDOException',消息为“SQLSTATE[42000],我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39886488/